anonymous
  • anonymous
in a certain year, the amount A of garbage in pounds produced afte t days by an average household is given by A=6.5t. How many days did it take for the average household to produce 150 pounds of garbarge?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
"How many days did it take for the average household to produce 150 pounds of garbarge?"\[ A = 150 \]We can substitute this into the equation already provided: \[ A=150 = 6.5t \]Now we just need to solve for \(t\)\[ 150 = 6.5t \]
anonymous
  • anonymous
\[6.5t \]This is actually multiplication: \[ 6.5\times t \]The inverse is division \[ (6.5\times t)\div 6.5 = t \]If we do this to both sides of the equation simultaneously: \[ 150\div 6.5 = (6.5\times t)\div 6.5 \\ 150\div 6.5 = t \]
anonymous
  • anonymous
23 days

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anonymous
  • anonymous
After 23 days, the average household will have produced just under 150 pounds of garbage. On the 24th day they have produced over 150 pounds.
anonymous
  • anonymous
The real question is, do you think you could solve a similar problem on your own from now on?
anonymous
  • anonymous
yeah now i just have to graph it
anonymous
  • anonymous
how would you graph it if i am off a smudge it will be wrong

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