anonymous
  • anonymous
Medal will be awarded :) workings please -Calculate the pH of the following aqueous solutions at 25°C, with the [OH–] equal to: 9.3 x 10^-10
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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aaronq
  • aaronq
use: pOH=-log\([OH^-]\); pH+pOH=14
anonymous
  • anonymous
what does pOH stand for again @aaronq
aaronq
  • aaronq
it's the negative logarithm of the hydroxide ion concentration (essentially a measure of the hydroxide ion concentration).

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anonymous
  • anonymous
umm hmm in simpler terms? or could you possibly show me the workings ?
aaronq
  • aaronq
just plug it into the formula, like you would for "pH=-log\([H_3O^+]\)"
anonymous
  • anonymous
i know that formula and i did that but my answer is app not correct :/
aaronq
  • aaronq
pOH=-log\((9.3*10^{-10})\) then, since pH+pOH=14, pH=14-pOH
anonymous
  • anonymous
thats what i did but the answer says 4.79
aaronq
  • aaronq
i got 4.968482948553936
anonymous
  • anonymous
how what did you plug in where?
aaronq
  • aaronq
read what i wrote just before
anonymous
  • anonymous
ok thanks
aaronq
  • aaronq
no problem. let me know if you still don't get it

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