anonymous
  • anonymous
Please Help Functions See Attachment
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
anonymous
  • anonymous
Not sure what the last two points are
zzr0ck3r
  • zzr0ck3r
so you want x value/s for when y = 2.5

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

zzr0ck3r
  • zzr0ck3r
for to y = 2.5, find the graph and then find the x
anonymous
  • anonymous
Is the answer three? or is it nonexistent @zzr0ck3r
zzr0ck3r
  • zzr0ck3r
f(3) = 3 I would say about f(2.5) = 2.5
anonymous
  • anonymous
I put that in and it said it was wrong...@zzr0ck3r
mathstudent55
  • mathstudent55
At \(f(x) = 2.5\), \(x \approx 2.8 \).
zzr0ck3r
  • zzr0ck3r
its a guessing game, I got bad eyes:)
zzr0ck3r
  • zzr0ck3r
bad question for them to put on a computer graded question
mathstudent55
  • mathstudent55
I agree. I think the important thing here is that there is only one value of x that gives f(x) = 2.5, whereas there are two values of x that give f(x) = 0.
anonymous
  • anonymous
than you @zzr0ck3r and @mathstudent55
mathstudent55
  • mathstudent55
wlcm

Looking for something else?

Not the answer you are looking for? Search for more explanations.