anonymous
  • anonymous
how do i do x \mapsto \frac{1}{\sqrt{3 x+13}}?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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zzr0ck3r
  • zzr0ck3r
what is mapsto?
zzr0ck3r
  • zzr0ck3r
\[x\mapsto\frac{1}{\sqrt{3x+13}}\]
zzr0ck3r
  • zzr0ck3r
what is the qestion?

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anonymous
  • anonymous
I'm sorry. I have no idea, I just copy pasted the equation. I have to find the domain of the function {1}{\sqrt{3 x+13}}?
zzr0ck3r
  • zzr0ck3r
ahh so we cant divide by 0, and we cant take the square root of a negative number so we have to make sure both of these dont happen we can do this buy finding out what x's make this a true statement 3x+13>0 do you understand why?
anonymous
  • anonymous
why?
zzr0ck3r
  • zzr0ck3r
well if we let a = 3x+13 we have \[\frac{1}{\sqrt{a}}\]now it should be easy to see why we need a to be greater than 0, and why a cant be 0 do you why a>0 is a must?
anonymous
  • anonymous
yes
zzr0ck3r
  • zzr0ck3r
ok so we said the thing in the square root, which is in the denominator must be greater than 0 so 3x+13 must be > 0
anonymous
  • anonymous
okay
zzr0ck3r
  • zzr0ck3r
you will basiccally have 3 problems with domain 1) square root of negative numbers 2) dividing by 0 3) taking log of non positive numbers
zzr0ck3r
  • zzr0ck3r
basically*
zzr0ck3r
  • zzr0ck3r
in this example you had both 1) and 2)
anonymous
  • anonymous
okay
zzr0ck3r
  • zzr0ck3r
when I find domain, I dont look for things that x CAN be, I look for things x CANT be.
anonymous
  • anonymous
thanks!
zzr0ck3r
  • zzr0ck3r
np

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