anonymous
  • anonymous
prove this formula
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[R = \sqrt{|a ^{2}| + |b ^{2}| + |a||b|\cos \theta}\]
anonymous
  • anonymous
and this formula:
anonymous
  • anonymous
\[R = \sqrt{|a ^{2}|+|b ^{2}| - |a||b|\cos \theta} \]

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dumbcow
  • dumbcow
what are these formulas in reference to? given the constants a,b,theta ... the 2 formulas seem to contradict each other if "R" is same in each
AkashdeepDeb
  • AkashdeepDeb
To prove these you need to use the Parallelogram Law of Vector addition where you get the magnitude resultant vector(R) of the 2 vectors A and B inclined at angle theta. Understood? :)
anonymous
  • anonymous
@dumbcow , these formulas are used about "Vectors". @AkashdeepDeb , No I didn't understand! can you prove or explain it more?
AkashdeepDeb
  • AkashdeepDeb
Yes, hold on a sec.
anonymous
  • anonymous
Thank you :)
zzr0ck3r
  • zzr0ck3r
you have that R equals two different things.
AkashdeepDeb
  • AkashdeepDeb
1 Attachment
AkashdeepDeb
  • AkashdeepDeb
And for proving R equals the second one just take a the vectors with the same magnitude but one vector in the opposite direction! :) Understood? :)
anonymous
  • anonymous
@AkashdeepDeb , Thank you,Thank you!I understood it!!! @zzr0ck3r , NO!This is two different formula!
AkashdeepDeb
  • AkashdeepDeb
:)

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