anonymous
  • anonymous
Can you separate the equation below (y^2+2xy)y' + y^2 = 7x into the form of exact equation: M(x,y) dx + N(x,y) dy = 0 ? It seem like impossible ?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
as you should know: y'=dy/dx, so (y^2+2xy)(dy/dx)= 7x- y^2 then: (y^2+2xy)dy= (7x- y^2)dx
anonymous
  • anonymous
Sorry, how did you get 7x ?
anonymous
  • anonymous
but.... are we supposed to move the x to the right and y to the left?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
i mean there is still variable y in the dy equation.
anonymous
  • anonymous
no: the finale shude be: (y^2+2xy)dy- (7x- y^2)dx =0
anonymous
  • anonymous
ok... my bad....
anonymous
  • anonymous
that's not important. You what exact equation is?
anonymous
  • anonymous
I was confused with the separable equation.. hahaha
anonymous
  • anonymous
ok, :)
anonymous
  • anonymous
thanks a lot....
anonymous
  • anonymous
yw
anonymous
  • anonymous
I cannot give two best answer
anonymous
  • anonymous
Thanks myko
goformit100
  • goformit100
"Welcome to OpenStudy. I can answer your questions or guide you. Please use the chat for off topic questions. And remember to give the helper a medal, by clicking on "Best Answer". We follow a code of conduct, ( http://openstudy.com/code-of-conduct ). Please take a moment to read it."

Looking for something else?

Not the answer you are looking for? Search for more explanations.