GoldPhenoix
  • GoldPhenoix
If m ≠ 0 and m ≠ 1, m~ = (m/m^2-m). What is the value of 6~ - (-5)~ ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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GoldPhenoix
  • GoldPhenoix
I know that 6~ = (1/5) So it would look like, (1/5) - (-5)~ I'm not sure what to do next.
GoldPhenoix
  • GoldPhenoix
Answer Choices: A. (1/30) B. (1/20) C. (1/4) D. (11/30) E. (9/20)
asnaseer
  • asnaseer
you did the first part correctly by substituting m=6 into the expression. For the second part, just substitute m=-5 into the expression.

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More answers

GoldPhenoix
  • GoldPhenoix
|dw:1378052434895:dw| Then you do (1/5) - (1/6) ?
asnaseer
  • asnaseer
be careful with your signs, in the denominator \[(-5)^2=25\]
GoldPhenoix
  • GoldPhenoix
So its A?
GoldPhenoix
  • GoldPhenoix
Ohh. Dammit.
asnaseer
  • asnaseer
\[m^2-m=(-5)^2-(-5)=?\]
GoldPhenoix
  • GoldPhenoix
25 + 5 = 30. So -5/30 = -1/6.
asnaseer
  • asnaseer
correct :)
GoldPhenoix
  • GoldPhenoix
Do you do, 1/5 - 1/6 or 15 - (-1/6) ?
GoldPhenoix
  • GoldPhenoix
1/5 - ( - 1/6)*
asnaseer
  • asnaseer
yes - the last one you typed is the correct way forward
GoldPhenoix
  • GoldPhenoix
Ah thanks. So 1/5 - (- 1/6) = 11/30. So its D. Thanks. :)
asnaseer
  • asnaseer
yes - and yw :)

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