anonymous
  • anonymous
Hi can you integrate (-2x^2-x) / (2x^3+x^2+1) with respect to x?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
you may need to decompose using the partial fractions technique
anonymous
  • anonymous
ohh i thought u are going to show it up.
anonymous
  • anonymous
but thanks for the tips...

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anonymous
  • anonymous
Hai UnkleRhaukus? Are you writing an answer?
anonymous
  • anonymous
I will give the best answer to him. If not..
UnkleRhaukus
  • UnkleRhaukus
can you do some thing tricky and make the integrand du/u ?
UnkleRhaukus
  • UnkleRhaukus
hmm , it dosen't quite work
anonymous
  • anonymous
is it possible to integrate ?
anonymous
  • anonymous
6x^2+2x doesn't quite make it nice and simple
anonymous
  • anonymous
-x(2x+1) look to see if 2x+1 is a factor of the bottom
anonymous
  • anonymous
i dont think it is.. right?
anonymous
  • anonymous
you can check if you'd like
anonymous
  • anonymous
ok. checking.
anonymous
  • anonymous
nope... it's not
anonymous
  • anonymous
nope...
anonymous
  • anonymous
-1 is a root
anonymous
  • anonymous
Other than partial fraction. is there any shorcut to do this integration ?
anonymous
  • anonymous
i mean any other method. don't care if it's hard.
anonymous
  • anonymous
not that i can think of right now
anonymous
  • anonymous
is it a definite or indefinite integral?
anonymous
  • anonymous
indefinite.
anonymous
  • anonymous
if it is finite, i can just use calculator ;P
anonymous
  • anonymous
hmmm...
anonymous
  • anonymous
see what you get after factoring out the root at -1. partial fraction decomp may be all you have. it's not that bad to use. have you learned it already?
anonymous
  • anonymous
i think doing factoring with that imaginary root will make this problem more complex.
anonymous
  • anonymous
i think, it's better i skip this question.
anonymous
  • anonymous
no... you leave that as a quadratic if you get a complex root
UnkleRhaukus
  • UnkleRhaukus
but, partial fractions is fun
anonymous
  • anonymous
it really is kind of cool, but takes a little bit of work
anonymous
  • anonymous
it's ok. i think i will leave this question.. by the way 2 of you are helping me.. but i have to give pgpilot326 as he's trying hard to help me.
anonymous
  • anonymous
thx for that... i'll see what i come up with on the decomp
anonymous
  • anonymous
thanks
anonymous
  • anonymous
\[\frac{ -2x ^{2}-x }{ 2x ^{3}+x ^{2}+1 }=\frac{ -\frac{ 1 }{ 4 } }{ x+1 }+\frac{ -\frac{ 3 }{ 2 } x+\frac{ 1 }{ 4 }}{ 2x^2 - x+1 }\]

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