anonymous
  • anonymous
Explain why (–4x)0 = 1, but –4x0 = –4.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Loser66
  • Loser66
use draw box below to write the problem, please. I don't understand a word
asnaseer
  • asnaseer
I think the asker is asking this:\[(-4x)^0=1\]\[-4x^0=-4\]
asnaseer
  • asnaseer
@Bea_26 -- am I right?

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More answers

anonymous
  • anonymous
Yep
asnaseer
  • asnaseer
ok, are you aware that \[a^0=1\]
anonymous
  • anonymous
Yep
asnaseer
  • asnaseer
for any \(a\) (apart from zero which has some controversy)
asnaseer
  • asnaseer
ok, good, so can you see that:\[(-4x)^0=(a)^0=a^0=1\]if we let \(a=-4x\)
anonymous
  • anonymous
order of operations
asnaseer
  • asnaseer
@Bea_26 -- Have you heard of PEMDAS
anonymous
  • anonymous
@asnaseer Yes I Have.
asnaseer
  • asnaseer
that is what @pgpilot326 is trying to explain now
asnaseer
  • asnaseer
in the second case you have:\[-4x^0\]so you need to perform the Exponent operation first, and then the multiplication to get:\[-4x^0=-4\times x^0=-4\times 1=-4\]
asnaseer
  • asnaseer
does that make sense?
anonymous
  • anonymous
A Little.
asnaseer
  • asnaseer
which part is troubling you?
anonymous
  • anonymous
we know that any number raised to the power of zero is one. but the exponent only assume the value right below it so -4x^0 actually means -4* x^0 but when you use parenthesis such as in the case of (-4x)^0 you have to treat -4x as a single value since -4x must be evaluated before evaluating the power. in other words (-4x)^0 = -4^0 * x^0 = 1* 1 = 1
anonymous
  • anonymous
@asnaseer , The Last Part.
asnaseer
  • asnaseer
|dw:1378058047586:dw|
asnaseer
  • asnaseer
The exponent has to be performed BEFORE the multiplication
asnaseer
  • asnaseer
e.g.\[-4x^3=-4\times x^3=-4\times x\times x\times x\]\[-4x^3\ne-4x\times-4x\times-4x\]

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