anonymous
  • anonymous
Vector A⃗ , which is shown in the figure, has a magnitude of 10 and a direction angle of 60º. What is the magnitude and direction angle (as measured counterclockwise from the positive x-axis) of −A⃗ /2? http://session.masteringphysics.com/problemAsset/1445605/2/PLCQ_ArtMs_Topic02_Q03_v2.jpg -5, 60º 5, 240º 5, -30º -5, -30º -5, 240º
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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theEric
  • theEric
Okay! So, you have \(\vec A\). Do you know what happens when you divide it by \(2\)?
anonymous
  • anonymous
goes to 5
theEric
  • theEric
Right! It's \(\sf length\) becomes \(5\). And now, what happens when you make it negative?

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anonymous
  • anonymous
its below the x axis
theEric
  • theEric
It really makes the vector point in the opposite direction.|dw:1378061032130:dw|
anonymous
  • anonymous
okay
theEric
  • theEric
That is a \(180^\circ\) rotation. The magnitude of a vector is always positive. So you're magnitude goes to \(5\) and your angle goes to... what?
anonymous
  • anonymous
240
theEric
  • theEric
Right! \(180^\circ+60^\circ=240^\circ\)
theEric
  • theEric
So, now you have your answer!
anonymous
  • anonymous
thanks
theEric
  • theEric
You're welcome! :)

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