anonymous
  • anonymous
6/a + 6/b
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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jim_thompson5910
  • jim_thompson5910
what is the LCD
anonymous
  • anonymous
6 6 - + - this is what it looks like a b
jim_thompson5910
  • jim_thompson5910
what are the denominators in this case

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anonymous
  • anonymous
a and b
jim_thompson5910
  • jim_thompson5910
since they have no common factors between them (other than 1), this means that the LCM of a and b is ab you just multiply the two terms if they have no common factors between them
jim_thompson5910
  • jim_thompson5910
so this means that the LCD is ab how can we use this to add the fractions?
anonymous
  • anonymous
well i adding but that wasn't it either
jim_thompson5910
  • jim_thompson5910
in order to add the fractions, the denominators must be the same
jim_thompson5910
  • jim_thompson5910
to get them to the same expression, we need to get them equal to the LCD
jim_thompson5910
  • jim_thompson5910
in the fraction 6/a, what is missing to get the LCD?
anonymous
  • anonymous
im not sure
jim_thompson5910
  • jim_thompson5910
what was the LCD again?
anonymous
  • anonymous
a and b do i need to flip them
jim_thompson5910
  • jim_thompson5910
the LCD is ab
jim_thompson5910
  • jim_thompson5910
so if we have the denominator 'a' and an LCD ab what's missing?
anonymous
  • anonymous
b
jim_thompson5910
  • jim_thompson5910
good
jim_thompson5910
  • jim_thompson5910
so you need to multiply top and bottom of the first fraction 6/a by b like this \[\large \frac{6}{a} \times \frac{b}{b}\] \[\large \frac{6\times b}{a\times b}\] \[\large \frac{6b}{ab}\]
jim_thompson5910
  • jim_thompson5910
do you see what to do with the other fraction?
anonymous
  • anonymous
and with 6/b i do the same
jim_thompson5910
  • jim_thompson5910
yes, you multiply top and bottom by ______ (fill in the blank)
anonymous
  • anonymous
a
jim_thompson5910
  • jim_thompson5910
good
jim_thompson5910
  • jim_thompson5910
doing that means you'll have this \[\large \frac{6}{b} \times \frac{a}{a}\] \[\large \frac{6\times a}{b\times a}\] \[\large \frac{6a}{ab}\]
jim_thompson5910
  • jim_thompson5910
So \[\large \frac{6}{a} + \frac{6}{b}\] turns into \[\large \frac{6b}{ab} + \frac{6a}{ab}\] what's next?
anonymous
  • anonymous
then it looks like 12ab/ab
jim_thompson5910
  • jim_thompson5910
close, but you cannot add 6a and 6b to get 12ab
jim_thompson5910
  • jim_thompson5910
the only thing you can do is this \[\large \frac{6b}{ab} + \frac{6a}{ab}\] \[\large \frac{6b+6a}{ab}\]
anonymous
  • anonymous
6a + 6b
jim_thompson5910
  • jim_thompson5910
yep, that's all you can do is add the numerators, but not actually combine them because they aren't like terms
jim_thompson5910
  • jim_thompson5910
optionally you could factor out 6, but that's extra work
anonymous
  • anonymous
Thanks
jim_thompson5910
  • jim_thompson5910
you're welcome

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