anonymous
  • anonymous
Hey intelligent helppppp and explain if you can this for me!!! Pleaseeeeeee!!!! In the isosceles triangle below , if segment BE is the perpendicular bisector of segment AD, what is the value of x?? I' ll send the figure .
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
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jdoe0001
  • jdoe0001
the triangle below where? below the screen maybe, because it's not ON the screen
anonymous
  • anonymous
|dw:1378064869500:dw|
anonymous
  • anonymous
there it is Jdoe

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anonymous
  • anonymous
any idea how to help me!!!
jdoe0001
  • jdoe0001
well, do you know what a bisector mean?
jdoe0001
  • jdoe0001
do you know what an isosceles triangle is?
anonymous
  • anonymous
Bisector is the line that cut an angle in half
jdoe0001
  • jdoe0001
is perpendicular, so that means it hits the bottom line AD right in the middle of it straight up, and it hits the vertex up above an isosceles triangle is a triangle with 2 EQUAL SIDES well, from the bisector there, we can pretty much tell who are those 2 equal sides it's definitely not the bottom AD so, which do you think are the equal sides there?
anonymous
  • anonymous
equal sides the triangles
anonymous
  • anonymous
so what does has to do with value of x??
jdoe0001
  • jdoe0001
well, which ones are the 2 equal sides you think?
anonymous
  • anonymous
ABE and EBD
jdoe0001
  • jdoe0001
sides. no triangles , just the sides, legs
anonymous
  • anonymous
90 degree??
jdoe0001
  • jdoe0001
|dw:1378066354669:dw|
anonymous
  • anonymous
ha ha ha you are hilarious
anonymous
  • anonymous
ok
jdoe0001
  • jdoe0001
so you have a triangle, it has 3 sides/legs, is an isosceles, that means 2 of those sides/legs are equal so which SIDES do you think might be the equal ones in that triangle?
anonymous
  • anonymous
AE and ED
anonymous
  • anonymous
oh AE and ED
anonymous
  • anonymous
AB and BD
anonymous
  • anonymous
sorry your leg makes me laugh
jdoe0001
  • jdoe0001
hmm, well yes... ahemm lemme put it differently the segment BE is not part of the isosceles triangle so your isosceles triangle is just \(\bf \measuredangle ABD\)
anonymous
  • anonymous
yes
jdoe0001
  • jdoe0001
so yes, if we skip the bisector, is just, you're correct, AB and BD notice how long AB is notice how long BD is also notice that AB = BD # since they're equal sides
anonymous
  • anonymous
but what about the equation at each side of this whole thing?
jdoe0001
  • jdoe0001
the equation on the side is "how long they are"
anonymous
  • anonymous
how long but could you show me how to solve this??
jdoe0001
  • jdoe0001
so we can say that AB is "4x + 5" long we can also say that BD is "2x + 10" long we know those 2 sides are the equal ones in the isosceles triangle, so AB = BD
anonymous
  • anonymous
so AB= 1 BD =5??
jdoe0001
  • jdoe0001
well, no, if that were true, AB = 1, BD =5 we know they're equal, BUT \(\bf 1 \ne 5\)
anonymous
  • anonymous
you are right I never thought of that
jdoe0001
  • jdoe0001
AB = 4x +5 BD = 2x + 10 AB = BD # if we substitute there, how would it look like?
jdoe0001
  • jdoe0001
\(\bf AB = \color{red}{4x +5}\\ BD = \color{blue}{2x + 10}\\ ------------------\\ \color{red}{AB} = \color{blue}{BD} \implies \square ?\)
anonymous
  • anonymous
4x + 5 + 2x + 10= 2.5
jdoe0001
  • jdoe0001
well, you're missing an equal, but yes, you're correct, x = 5/2 = 2.5
anonymous
  • anonymous
so here it is like a regular equation grouping
jdoe0001
  • jdoe0001
because 4x+5 = 2x+10 x = 5/2
anonymous
  • anonymous
yes I was showing you my result but all nothing have to do with triangle
jdoe0001
  • jdoe0001
so, that's "x" :)
anonymous
  • anonymous
thanks a lot
jdoe0001
  • jdoe0001
yw

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