anonymous
  • anonymous
d^9/d^6 = (whole number)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
what's the question?
anonymous
  • anonymous
give corresponding whole number
anonymous
  • anonymous
reduce the left hand side

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
are there any limitations on d?
anonymous
  • anonymous
seems like it would be 1, because there is no whole number, only exp.
anonymous
  • anonymous
just d^9\ d^6
anonymous
  • anonymous
d^3 = whole number
anonymous
  • anonymous
d could be any whole number or cube root or whole number times cube root
anonymous
  • anonymous
so then wouldn't it just be 1, as d is understood as 1?
anonymous
  • anonymous
why is d understood to be 1?
anonymous
  • anonymous
just comparing to a linear equation? i don't know:(
geerky42
  • geerky42
\(\Huge d = \sqrt[3]{x}, x \in \mathbb{Z}\)
anonymous
  • anonymous
\[x \in \mathbb{Z}^+\]
anonymous
  • anonymous
whole number
anonymous
  • anonymous
actually \[ x \in \mathbb{Z}^*\]
geerky42
  • geerky42
Or \(\large\mathbb{N} \)

Looking for something else?

Not the answer you are looking for? Search for more explanations.