anonymous
  • anonymous
HELP PLEASE!! MEDALS WILL BE GIVEN!! Solve the system of equations: 9a+3b+c=2 a+b+c=4 6a+b=0
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Pick one equation and solve for one variable. It doesn't matter which one. Show me your work and I will give you the next step.
anonymous
  • anonymous
b=-6a
anonymous
  • anonymous
Great. Now substitute -6a for b in one of the other equations.

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anonymous
  • anonymous
9a + 3(-6a) +c =2
anonymous
  • anonymous
so that equals to -9a+c=2
anonymous
  • anonymous
Now substitute the same -6a for b in the other 3 variable equation. That should leave you with 2 equations and 2 variables.
anonymous
  • anonymous
a + -6a +c =4 -5a +c =4
anonymous
  • anonymous
so then c= 4 +5a
anonymous
  • anonymous
Don't solve for c on this one. Your two equations are: -9a+c=2 -5a+c=4 Can you solve a systems of equations with two variables? I would suggest subtraction....
anonymous
  • anonymous
alright thank you :) i got it from here :)
anonymous
  • anonymous
Great. If you need an additional resource, www.purplemath.com is a great resource for high school math.

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