anonymous
  • anonymous
a certain mountain has elevation of 19,515 feet.in 1915, the glacier on this peak covered 6 acres.by 2002 this glacier had melted to only 1 acre. (a) assume that this glacier melted at a constant rate each year.find this yearly rate. (b) use your awser form part(a) to wite a linear equation that gives the acreage a of this glacier t years past 1915. the yearly rate of change is__acres/year. what is the equation that gives the acreage of the glacier t yaers after 1915?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
im lost
anonymous
  • anonymous
use the points (0, 6) and (87, 1) to find the slope, or m, also the yearly rate of change. I got 87 because that is how many years elapsed from 1915 to 2002. If the equation has to be in standard form, use y=mx+b. You already will have solved for m, and then use the first x,y coordinate to determine b. This will give you the equation
anonymous
  • anonymous
(87/2,7/2)

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anonymous
  • anonymous
are you thinking of the midpoint formula? Slope would be (y2-y1)/(x2-x1)
anonymous
  • anonymous
im lost
anonymous
  • anonymous
ok it 87 acres
anonymous
  • anonymous
a year
anonymous
  • anonymous
slope=m= (1-6)/ (87-0) = -5/87 acres/year which intuitively makes sense that its negative because the glacier size is decreasing. This was derived by finding the change in y (5 acres over that period of time) divided by the elapsed time (87 years)
anonymous
  • anonymous
5/87 acres/year
anonymous
  • anonymous
actually \(-\frac{5}{87}\) since they are decreasing
anonymous
  • anonymous
so if \(x\) is the number of years after 1915 then the equation would be \[y=-\frac{5}{87}x+6\]
anonymous
  • anonymous
the reason for the \(6\) out at the end is because that is what you started with i.e. if \(x=0\) then \(y=6\)

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