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2nd half http://gyazo.com/e275663cf44f07e7058f7fe44584d651
what is the function..
Haha whoops sorry thought it was in the first picture http://gyazo.com/8fee6934c1a3bccbf623b19b3bafaff1
what is you opinion a)?
A) 4 then for the 2nd question, A) 5
let's solve this first http://gyazo.com/f92270ef2f6072d7b4345c9fc3b1feac
Sorry I mixed up the lefts and rights ;P
that's fine b)?
a) is correct
So it's all correct, right?
in order to be undefined, there should be a vertical asymptote, like I sent a graph one
if graph is something like this, it is undefined at dashed point
So then how do I find the answer? o.O It has two points in which it is defined, or is it 4 because its the unopened circle?
Okay so then D is A
existence of value is not enough to have for continuity
So it's B, but how is an existance of a value not enough? can you show me an example?
first limit must exist at that point, also value of function must be equal limit
the reason is limit DNE, because left right limits are not equal..
Oooooo right, sorry. I was looking at the past question and seeing f(3) exists, so that made me think that it was indeed contin.
Last question http://gyazo.com/846c5f6bf030ef660d9bb4247bc74d6d
what is right limit..
if x>5 which func. we should use..
what is the value of func.
So thus the answer is A?
good, limit ->5+=15
how about left limit..
if x<5 which func. we should use..
2x^2-5x-25/x-5, which simplified down is 2x+5
good and what is the value of func.
so that limit ->5=15 because limit ->5=15 =limit ->5+=15 =limit ->5-=15 last thing is f(15)?
f(5)=lim->5 f(x)=15 thus f(x) is cont. at x=5
You are a life saver:)
Thank you so much haha. I used to be so good at math then I took a two year break, such a bad idea!