Lukecrayonz
  • Lukecrayonz
Limits:) @cinar
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Lukecrayonz
  • Lukecrayonz
http://gyazo.com/f92270ef2f6072d7b4345c9fc3b1feac
Lukecrayonz
  • Lukecrayonz
2nd half http://gyazo.com/e275663cf44f07e7058f7fe44584d651
anonymous
  • anonymous
what is the function..

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Lukecrayonz
  • Lukecrayonz
Haha whoops sorry thought it was in the first picture http://gyazo.com/8fee6934c1a3bccbf623b19b3bafaff1
anonymous
  • anonymous
what is you opinion a)?
Lukecrayonz
  • Lukecrayonz
A) 4 then for the 2nd question, A) 5
anonymous
  • anonymous
a)5
anonymous
  • anonymous
let's solve this first http://gyazo.com/f92270ef2f6072d7b4345c9fc3b1feac
anonymous
  • anonymous
a)5
Lukecrayonz
  • Lukecrayonz
Sorry I mixed up the lefts and rights ;P
Lukecrayonz
  • Lukecrayonz
http://gyazo.com/54417b22c596fd41bcdc87881b00dba0
anonymous
  • anonymous
that's fine b)?
anonymous
  • anonymous
a) is correct
Lukecrayonz
  • Lukecrayonz
So it's all correct, right?
anonymous
  • anonymous
yes..
anonymous
  • anonymous
f(3)=?
Lukecrayonz
  • Lukecrayonz
undefined
anonymous
  • anonymous
in order to be undefined, there should be a vertical asymptote, like I sent a graph one
anonymous
  • anonymous
|dw:1378092550000:dw|
anonymous
  • anonymous
if graph is something like this, it is undefined at dashed point
Lukecrayonz
  • Lukecrayonz
So then how do I find the answer? o.O It has two points in which it is defined, or is it 4 because its the unopened circle?
anonymous
  • anonymous
yes
Lukecrayonz
  • Lukecrayonz
Okay so then D is A
anonymous
  • anonymous
existence of value is not enough to have for continuity
Lukecrayonz
  • Lukecrayonz
So it's B, but how is an existance of a value not enough? can you show me an example?
anonymous
  • anonymous
first limit must exist at that point, also value of function must be equal limit
anonymous
  • anonymous
d)C
anonymous
  • anonymous
the reason is limit DNE, because left right limits are not equal..
Lukecrayonz
  • Lukecrayonz
Oooooo right, sorry. I was looking at the past question and seeing f(3) exists, so that made me think that it was indeed contin.
Lukecrayonz
  • Lukecrayonz
Last question http://gyazo.com/846c5f6bf030ef660d9bb4247bc74d6d
anonymous
  • anonymous
what is right limit..
anonymous
  • anonymous
if x>5 which func. we should use..
Lukecrayonz
  • Lukecrayonz
7x-20
anonymous
  • anonymous
right..
anonymous
  • anonymous
what is the value of func.
Lukecrayonz
  • Lukecrayonz
15
Lukecrayonz
  • Lukecrayonz
So thus the answer is A?
anonymous
  • anonymous
good, limit ->5+=15
anonymous
  • anonymous
hold on..
anonymous
  • anonymous
how about left limit..
anonymous
  • anonymous
limit ->5-=?
anonymous
  • anonymous
if x<5 which func. we should use..
Lukecrayonz
  • Lukecrayonz
2x^2-5x-25/x-5, which simplified down is 2x+5
anonymous
  • anonymous
good and what is the value of func.
Lukecrayonz
  • Lukecrayonz
15
anonymous
  • anonymous
so that limit ->5=15 because limit ->5=15 =limit ->5+=15 =limit ->5-=15 last thing is f(15)?
Lukecrayonz
  • Lukecrayonz
Huh?
Lukecrayonz
  • Lukecrayonz
f(5)=15
anonymous
  • anonymous
sorry f(5)?
anonymous
  • anonymous
f(5)=lim->5 f(x)=15 thus f(x) is cont. at x=5
Lukecrayonz
  • Lukecrayonz
You are a life saver:)
anonymous
  • anonymous
(:
anonymous
  • anonymous
gotta go..
Lukecrayonz
  • Lukecrayonz
Thank you so much haha. I used to be so good at math then I took a two year break, such a bad idea!

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