anonymous
  • anonymous
Each of the displacement vectors A and B shown have a magnitude of 3.00m.? Graphically find: A) A + B B) A - B C) B- A D) A - 2B http://www.webassign.net/serpop/p1-38.gi… this is the picture the back of the book gives the answers but i dont understand how they got it! PLEASE RESPOND ASAP!
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
http://www.webassign.net/serpop/p1-38.gif
anonymous
  • anonymous
What exactly do you want?
anonymous
  • anonymous
@verooo97 ,

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More answers

anonymous
  • anonymous
the magnitude and direction of a b c d @PFEH.1999
anonymous
  • anonymous
|dw:1378095967810:dw|
anonymous
  • anonymous
in the back of the book it says a) 5.2 m at 60 deg. b) 3 m at 30 deg below + x axis c) 3 m @ 150 deg. counter clockwise from the + x axis d) 5.2 m at 60 deg. below + x axis. i dont understand how they got this answer
anonymous
  • anonymous
Ok,I will tell you ;)
anonymous
  • anonymous
\[\theta = 90 - 30 = 60\]
anonymous
  • anonymous
ok?
anonymous
  • anonymous
okay
anonymous
  • anonymous
|dw:1378096190115:dw|
anonymous
  • anonymous
R = A + B
anonymous
  • anonymous
then we have to find "R" OK?
anonymous
  • anonymous
ok
anonymous
  • anonymous
use his formula: \[R = \sqrt{|a ^{2}|+|b ^{2}|+2|a||b|\cos \theta}\]
anonymous
  • anonymous
use it...
anonymous
  • anonymous
okay
anonymous
  • anonymous
then you can solve "A",and then for solving B...
anonymous
  • anonymous
how would i get the direction of the resultant vector?
anonymous
  • anonymous
|dw:1378096465537:dw|
anonymous
  • anonymous
use this formula: \[R = \sqrt{|a ^{2}|+|b ^{2}| -2|a||b|\cos \theta}\]
anonymous
  • anonymous
and then,you can solve "B"
anonymous
  • anonymous
understood?
anonymous
  • anonymous
that formula is for b?
anonymous
  • anonymous
which one?the second formula?
anonymous
  • anonymous
yes
anonymous
  • anonymous
|dw:1378096661179:dw| yes,when we want to solve "a-b" or "b-a" we use the second formula...
anonymous
  • anonymous
okay i see, now how would it be set up for "d"?
anonymous
  • anonymous
|dw:1378096855389:dw|
anonymous
  • anonymous
okay now i see.
anonymous
  • anonymous
but I didn't find any formula!
anonymous
  • anonymous
wait and let me search...
anonymous
  • anonymous
OH YES!
anonymous
  • anonymous
I found!
anonymous
  • anonymous
|dw:1378097018343:dw|
anonymous
  • anonymous
ok
anonymous
  • anonymous
any problem?
anonymous
  • anonymous
i understand how to do this now, but how would i find the distance?
anonymous
  • anonymous
distance?can you draw?
anonymous
  • anonymous
im sorry i meant direction!
anonymous
  • anonymous
Oh,no problem :D the direction!!! I will draw 4 pictures for you :D
anonymous
  • anonymous
okay ! thank you so so so so so much !
anonymous
  • anonymous
|dw:1378097339297:dw| for A !
anonymous
  • anonymous
i dont understand?
anonymous
  • anonymous
Why?
anonymous
  • anonymous
what is that supposed to mean?
anonymous
  • anonymous
It mean the direction of vector "R" in first question!
anonymous
  • anonymous
okay
anonymous
  • anonymous
and the second one!
anonymous
  • anonymous
a -b
anonymous
  • anonymous
okay i dont understand this, in the book they get 60 deg. above the positive x axis, how did they get this??
anonymous
  • anonymous
Oh,Hmmm...I think in your country people say the direction like this! listen...60 deg is Theta!both you and I know!and "above the positive x axis" mean: The direction "R" is above the "x axis" not above the "y axis" OK?
anonymous
  • anonymous
okay
anonymous
  • anonymous
then you can find the direction of "A", "B" , "C" and D...but B and D are same...
anonymous
  • anonymous
ok. thanks for your help !
anonymous
  • anonymous
your welcome ;) the vectors are very very important in Physics...

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