anonymous
  • anonymous
Use basic identities to simplify the expression. sin2θ + tan2θ + cos2θ Choices are: sec2θ cos3θ sin θ tan2θ
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
This was all I got so far. I'm not sure what to do next! 1/csc+sin/cos+1/sec
DebbieG
  • DebbieG
Are you sure you've copied the problem down correctly? Even using a graphing tool, I'm not finding that any of those choices are equivalent to the original expression....?
anonymous
  • anonymous
Yes! Oh wait sorry, all the numbers are supposed to be exponents. sin^2θ + tan^2θ + cos^2θ sec^2θ cos^3θ sin θ tan^2θ

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DebbieG
  • DebbieG
ah-hah, that will make a big difference... ;)
DebbieG
  • DebbieG
so it's \(\sin^2\theta+\tan^2\theta+\cos^2\theta\), right?
anonymous
  • anonymous
yes!
DebbieG
  • DebbieG
Use your Pythagorean identities... specifically: \(\sin^2\theta+\cos^2\theta=1\) And also \(\tan^2\theta+1=\sec^2\theta\) Now that we have the right problem, it should be pretty trivial. :)
anonymous
  • anonymous
Is it tan^2θ? :O

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