anonymous
  • anonymous
I have folded one of the pages randomly of a book . The sum of the page numbers except the page which is folded is 15000. what are the pages that are folded?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
What ? Can you answer better ?!!!
goformit100
  • goformit100
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AkashdeepDeb
  • AkashdeepDeb
Argghhh.. I am getting one equation at this......

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More answers

anonymous
  • anonymous
what is it
AkashdeepDeb
  • AkashdeepDeb
If one page is folded that means x and the previous page of the same leaf is x-1 Forming an arithmetic progression for sum of consecutive numbers: n(n+1)/2 = 15000 + x + x-1 Understand this? :)
anonymous
  • anonymous
ya but how would u solve it
AkashdeepDeb
  • AkashdeepDeb
Yes..That's what has been boggling my mind for some hours now... Is there anything else given in the question? We need to get another equation! :D
anonymous
  • anonymous
sorry but nothing else was given in it but I am knowing the ans its 25 & 26
AkashdeepDeb
  • AkashdeepDeb
Tag some people see if they can help you or not! :D Tag them by putting '@'*theirusername* :)
anonymous
  • anonymous
i dont know how to tag someone
AkashdeepDeb
  • AkashdeepDeb
@Ayushi2103 ^ LIKE THAT! :D
anonymous
  • anonymous
but where to type it
anonymous
  • anonymous
ok i got it thanx
anonymous
  • anonymous
@goformit100
AkashdeepDeb
  • AkashdeepDeb
Try this: 15000 = (n-2)/2 * [a + (n-2 -1)d] where a=1,d=1 :D
anonymous
  • anonymous
does this work
AkashdeepDeb
  • AkashdeepDeb
I think so.. Because the sum is 15000 without including 2 pages so n-2 :D
anonymous
  • anonymous
i got the solution n(n+1)/2=>15000 by hit and trial 1+2+3...+173=15051 x+x+1=15051-15000 2x+1=51 2x=50 x=25 x+1=26
anonymous
  • anonymous
thanx for giving me the clue and helping me with it
AkashdeepDeb
  • AkashdeepDeb
Oh Awesome! :D
AkashdeepDeb
  • AkashdeepDeb
:)
anonymous
  • anonymous
we ll meet later on cauz i wanna go bye

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