uri
  • uri
Stats help: Q.14 Average rainfall of a certain city from Friday to Wednesday is 0.3.Due to heavy rainfall on Thursday,the average of the week increases to 0.5.What was the rainfall on Thursday?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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uri
  • uri
Using this formula:|dw:1378139451483:dw| @pgpilot326
anonymous
  • anonymous
\[\bar{x} \text{ not } \bar{n}\]
uri
  • uri
How do i make this on equation tool? and i know drawing tool kinda sucks eh.

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More answers

anonymous
  • anonymous
\[ \bar{x} \] is \bar{x}
anonymous
  • anonymous
\[\bar{x} = \frac{\sum_{i=1}^{n} x_i}{n}\]
uri
  • uri
Alright,DO you know how to do this...:D Help mee.Seen this formula for the first time. D:
anonymous
  • anonymous
the formula is just an expression of what is happening. don't overcomplicate it... an average is just a sum of numbers divided by the count of numbers in the sum. how many days are you summing the rainfall?
uri
  • uri
5 days?
anonymous
  • anonymous
nope... first do friday to wednesday. include those days as well. how many days is that?
nincompoop
  • nincompoop
I think someone is already helping you out, uriskicoocoo
anonymous
  • anonymous
how about 6?
uri
  • uri
wait ye.
anonymous
  • anonymous
okay, and what is the average for those days?
uri
  • uri
0.3
anonymous
  • anonymous
so what is this? \[ x_1 + x_2 + x_3 + x_4 + x_5 + x_6 =\]
uri
  • uri
I don't know.
anonymous
  • anonymous
\[n\cdot \bar{x} \]
uri
  • uri
here \[n =0.3\]
uri
  • uri
What will be \[ \bar{x} ?\]
anonymous
  • anonymous
remember \[\sum_{i=1}^{6} x_i = x_1 + x_2 + x_3 + x_4 + x_5 + x_6 = \bar{x}\cdot n\]
anonymous
  • anonymous
n = 6
nincompoop
  • nincompoop
you need to put definitions on that formula to start with so one is not walking in the dark trying to use it
uri
  • uri
I do not understand.How do i know that \[n=6 \]
anonymous
  • anonymous
n is the number of days you are using to compute your average. here, we are going ffrom friday to wednesday, inclusive. that is friday, sat, sun, mon, tues, weds... a total of six days. n will always be the number of objects you are summing in your average.
uri
  • uri
alright and how about\[\bar {x}\]
anonymous
  • anonymous
the \[x_i {'s}\] are the individual rainfall totals for a given day... so \[x_1 = \text {Friday's rainfall}\] \[x_2 = \text {Saturday's rainfall}\] etc. \[\bar{x} = \text{the average rainfall for those days}\]
uri
  • uri
Hmm so \[6* 0.3 =1.8\]
anonymous
  • anonymous
yes which is the sum of the rainfall for those days.
uri
  • uri
How to find the of thursday now.
anonymous
  • anonymous
now, they add one more day and the average changes (as does the number of days). but the sum for those first 6 days stays the same.
anonymous
  • anonymous
what's the new average?
anonymous
  • anonymous
\[\bar{x} = \frac { \left( x_1 + x_2 + x_3 + x_4 + x_5 + x_6 \right) + x_7}{7}\]
anonymous
  • anonymous
the average in this one is the new average (.5)
anonymous
  • anonymous
\[0.5 \cdot 7 = 1.8 + x_7\]
uri
  • uri
Wait, \[3.5=1.8=x7\] \[x7=1.7\]
uri
  • uri
@pgpilot326
anonymous
  • anonymous
there you go
uri
  • uri
Thanks.
anonymous
  • anonymous
you're welcome!
uri
  • uri
I joined school late.I'll take extra classes. :3

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