anonymous
  • anonymous
Polar coordinates question
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
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anonymous
  • anonymous
Hello there, Think about the polar co-ordinate notation \((r, \theta)\), where r stands for the radius, or distance from the origin to the point, and \(\theta\) stands for the angle from the \(x\)-axis. |dw:1378140856422:dw| Look at the drawing. Can the the radius change, and still be at the same point? Can the angle change and still be at the same point at the end?
anonymous
  • anonymous
it can right? @jlvm

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anonymous
  • anonymous
Answer the questions separately. Think about the radius one first, and tell me your answer.
anonymous
  • anonymous
well I feel like in order for it get back to its place it would have to be ((2pi+1)pi)
anonymous
  • anonymous
(2n*+1)pi
anonymous
  • anonymous
Remember, \(2\pi\) always gets you back to where you began. In fact, any even multiple of \(pi\) will do that. So, as long as the radius is 4, if you watnt to get back, what should the multiples of \(\pi \) be?
anonymous
  • anonymous
oh so it just needs to be 2npi because it just needs twice to get back? @jlvm
anonymous
  • anonymous
Yes. That's one of the two options.
anonymous
  • anonymous
When \(r\) is positive, in this case \(r=4\) that is the case. Now, what about when \(r=-4\)?
anonymous
  • anonymous
that's when it's going to have to switch to 2n+1)pi right?
anonymous
  • anonymous
@jlvm ???
anonymous
  • anonymous
Yes. :)
anonymous
  • anonymous
YAY!!! thank you :)

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