anonymous
  • anonymous
-4x^48 times 1/x^86
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
i get -4/x^-38
anonymous
  • anonymous
looks goodto me
anonymous
  • anonymous
I thought that as well, but the answer states it as \[-4/x^(38)\]

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More answers

anonymous
  • anonymous
But if I was right then we could re write it as -4x^38?
anonymous
  • anonymous
This is the real question.... limx→−∞−9x^86−4x^48−2 −2x86+7x46−10
anonymous
  • anonymous
oh i see i was wrong, sorry
anonymous
  • anonymous
Its Ok, I am just a little confused on why it doesnt seem to be adding up
anonymous
  • anonymous
\[\frac{-4x^{48}}{x^{86}}=\frac{-4}{x^{86-48}}=\frac{-4}{x^{36}}\]
anonymous
  • anonymous
ooh i see your question, answer has nothing to do with that at all
anonymous
  • anonymous
both numerator and denominator of your rational function are polynomials of degree 86
anonymous
  • anonymous
Ok, I thought the exponent rules were x^m/x^n = x^(m-n)
anonymous
  • anonymous
since the degrees are the same, the limit as \(x\to \infty\) is the ratio of the leading coefficients
anonymous
  • anonymous
which in your case is \(y=\frac{9}{2}\)
anonymous
  • anonymous
as for the rules of exponents, which i repeat has nothing to do with this question you are right \[\frac{x^m}{x^n}=x^{m-n}\]
anonymous
  • anonymous
Ok I think i am catching on, the rules change since the limit is approaching infinity?
anonymous
  • anonymous
no, the rules of exponents don't change at all
anonymous
  • anonymous
Ok I see the degree of 9 and 2 are to the 86th,
anonymous
  • anonymous
you are not being asked to divide you cannot divide term by term in any case
anonymous
  • anonymous
\[\frac{−9x^{86}−4x^{48}−2}{ −2x^{86}+7x^{46}−10}\] is your rational function
anonymous
  • anonymous
you cannot divide piece by piece you would have to divide using long division, but you are not asked to divide
anonymous
  • anonymous
you are asked for the horizontal asymptote since the degrees are the same, it is the ratio of the leading coefficients
anonymous
  • anonymous
the lower degrees are unimportant as you go to \(\infty\) so this really behaves just like \[\frac{-9x^{86}}{-2x^{86}}=\frac{9}{2}\]
anonymous
  • anonymous
Oh Awesome I see, I just saw exponets and when I tried the rule, it threw me for a loop
anonymous
  • anonymous
Oh Awesome I see, I just saw exponets and when I tried the rule, it threw me for a loop

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