anonymous
  • anonymous
how could you use 1.0M lactic acid and 1.0M NaOH (instead of lactate) to make 200ml of a 0.25M lactate buffer, ph 4.0? i dont know where to start
Chemistry
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schrodinger
  • schrodinger
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aaronq
  • aaronq
Start by looking at how much lactic acid and sodium lactate you would need for the buffer (200ml of a 0.25M lactate buffer, ph 4.0). Then you're going to find what proportions of lactic acid and NaOH you should mix to get the sodium lactate and lactic acid (because its not a strong acid and won't fully dissociate). \(CH_3CH(OH)COOH+ NaOH \rightarrow CH_3CH(OH)COO^-Na^+ + H_2O \) \(+\; CH_3CH(OH)COOH\)
anonymous
  • anonymous
how would tou calculate for what you will need
aaronq
  • aaronq
I'm pretty sure you can use the henderson-hasslebach equation

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anonymous
  • anonymous
yh i did i got 0.11 lactic acid, 0.14 lactate then i got stuck
anonymous
  • anonymous
M
aaronq
  • aaronq
Now find how much lactic acid and NaOH you need to mix to achieve that mixture.
anonymous
  • anonymous
thats where i am confused
aaronq
  • aaronq
You gotta think like a chemist. To get an idea, mix any amount and see what you end up with.
aaronq
  • aaronq
HINT: you have to do it in 2 parts, use the dissociation of lactic acid (equilibrium expression), and the neutralization to make sodium lactate.
anonymous
  • anonymous
so the first thing will be 1.0M under the eq. then under it will be 0.11M on the left side of the eq. and the right side will be 0.14 m..then i substracted both sides by 1.0M naoh .. however i got a - num on the left i am kind of puzzled
aaronq
  • aaronq
can you write it as an equation, i don't know what you mean. if you got a negative number you're doing i wrong.
anonymous
  • anonymous
|dw:1378147386781:dw|
anonymous
  • anonymous
this is how i did it please let me know if i am doin it wrong
aaronq
  • aaronq
hm i'm not sure what you're doing :S for lactic acid, use this: \(K_a=\dfrac{[H^+][CH_3CH(OH)COO^-]}{[CH_3CH(OH)COOH]}\)
anonymous
  • anonymous
so what values do i plug in

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