anonymous
  • anonymous
tracey leaves detroit at 8:00 am going 55mph, and kelly leaves at 10:00am going 65mph. when will kelley catch up with tracey
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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OakTree
  • OakTree
Give me a moment.
OakTree
  • OakTree
Okay. So are you ready to start solving?
OakTree
  • OakTree
Great. So what we want to do is solve for the time it takes. The easiest way to do this is by a table of distances. Do you know what that is?

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OakTree
  • OakTree
No, not like that. I mean like this:
OakTree
  • OakTree
|dw:1378147393355:dw| And then going down like that.
OakTree
  • OakTree
But there is a shortcut - do you want to know it?
OakTree
  • OakTree
Oh, that's silly. That forces you to write out too much work. But what you want to do is for T you want the amount of time since 8 o'clock and for D you just multiply R and T.
OakTree
  • OakTree
You still confused?
OakTree
  • OakTree
D = R x T.
OakTree
  • OakTree
Use your chart. Tracey's rate is 55, her time is t, and her distance is 55t. Kelley's rate is 65, her time is t-2, and her distance is 65(t-2). We want 55t to equal 65(t-2). Solve. Do you get it now?
OakTree
  • OakTree
Great.
OakTree
  • OakTree
What did you get?
OakTree
  • OakTree
Good, now keep going.
OakTree
  • OakTree
No, you subtract 55t from both sides and add 130 to both sides. Then you divide both sides by 10 and get t=13.
OakTree
  • OakTree
Not negative. Positive 13. And I would be willing to stake my life on it.
OakTree
  • OakTree
Points can't have x and y as their coordinates. That problem is badly written.
OakTree
  • OakTree
Oh, never mind, I get it. It's just \[\left| x-y \right|\]
OakTree
  • OakTree
No problem. A medal is more than enough! Glad to help.

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