anonymous
  • anonymous
Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary. B = 74°, a = 14 cm, c = 20 cm
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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AkashdeepDeb
  • AkashdeepDeb
Do you know the law of sines?
anonymous
  • anonymous
WOOO got it :D I found the answer as 134.58
AkashdeepDeb
  • AkashdeepDeb
Oh Great! :D

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More answers

anonymous
  • anonymous
wait let me check first, I used the formula 1/2acsinB?
anonymous
  • anonymous
LOL thank you xD but there is one more question I actually need help with about triangles, mind helping me?
AkashdeepDeb
  • AkashdeepDeb
Not at all.
anonymous
  • anonymous
yay thank you!! the question is Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. B = 49°, a = 16, b = 14
anonymous
  • anonymous
I am really finicky with law of sines D:
AkashdeepDeb
  • AkashdeepDeb
|dw:1378147440711:dw|
AkashdeepDeb
  • AkashdeepDeb
Do you know heron's formula?
anonymous
  • anonymous
yeah I know that formula!!! I think somewhere in the mix of me finding it I screw up LOL! let me try xD
AkashdeepDeb
  • AkashdeepDeb
Okay. :D
anonymous
  • anonymous
would A be 59.6??!
AkashdeepDeb
  • AkashdeepDeb
Hold on.
anonymous
  • anonymous
mmk :)
AkashdeepDeb
  • AkashdeepDeb
How much is sin inverse of 0.8252523?
AkashdeepDeb
  • AkashdeepDeb
Yes you are almost correct!! :D
AkashdeepDeb
  • AkashdeepDeb
I think it is 55.6 :D
anonymous
  • anonymous
omg woo :DDD
anonymous
  • anonymous
ok now what lol
anonymous
  • anonymous
@AkashdeepDeb I got C as 71.4 would c be 11.1 then?
AkashdeepDeb
  • AkashdeepDeb
I am not calculateing but If you are calculating then you are right! :D
anonymous
  • anonymous
LOL I mess up though!! :( crap. lol let me double check
AkashdeepDeb
  • AkashdeepDeb
Yes and then just use herons formula! By finding out s the semi-permiter \[\sqrt{s(s-a)(s-b)(s-c)}\]
anonymous
  • anonymous
I can't find little c
anonymous
  • anonymous
I feel like it's wrong way
anonymous
  • anonymous
nevermind I got the answer :D

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