anonymous
  • anonymous
Suppose we have a chessboard (contains 64 quods). In the first quod we put 0.01 € (1 cents) in the second squod double the previous one and continue this process until the 64th square, how much money we have put on the board?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Choose between: a) (263 -1)€ b) 0.01 . (263 -1)€ c) (264 -1)€ d) 0.01 . (264 -1)€
ganeshie8
  • ganeshie8
first form the sequence, then, find \(r\) and \(a\) after that, use series formula
anonymous
  • anonymous
i do not rember anything.. many years since school,,,

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More answers

ganeshie8
  • ganeshie8
1, 2, 4, 8, 16, 32 .....
ganeshie8
  • ganeshie8
ok, np :) chess board has how many squares ? 64 right ?
anonymous
  • anonymous
0.01, 0.0001, 0.00000001, 0.0000000000000001...............1,e-128
ganeshie8
  • ganeshie8
so, there will be 64 terms in the series :- \(\large 2^0, 2^1, 2^2, 2^3, 2^4, 2^5, ... \)
ganeshie8
  • ganeshie8
careful, it says first square we put 1 cent second square we put double
ganeshie8
  • ganeshie8
so, it must be like this :- \(\large 2^0, 2^1, 2^2, 2^3, 2^4, 2^5, ...\) 64 terms will be there
ganeshie8
  • ganeshie8
you familiar wid geometric series formula, to find sum of terms ?
anonymous
  • anonymous
no i do not rember
ganeshie8
  • ganeshie8
me neither... formula is not on top of my head. google and see if u can get the formula
anonymous
  • anonymous
i believe is 0.01 . (2^64 -1)€
ganeshie8
  • ganeshie8
thats correct ! how did u get to that ? :)
anonymous
  • anonymous
because the other answers are somehow idiots ;p
anonymous
  • anonymous
it cannot be 263-1
anonymous
  • anonymous
because the other answers are somehow idiots ;p
ganeshie8
  • ganeshie8
lol why not, how do u see that hmm
anonymous
  • anonymous
and it cannot be 2^64-1 ;p
anonymous
  • anonymous
because in the last there is no where the 0.01
ganeshie8
  • ganeshie8
thats good observation :)
anonymous
  • anonymous
and in the other cannot be 2^63-1
anonymous
  • anonymous
thank you for your help ;p
ganeshie8
  • ganeshie8
yes you're right !! np :)
ganeshie8
  • ganeshie8
there is a formula for this also :- \(\large total \ sum = a(\frac{r^n-1}{r-1})\) a = 1 r= 2 n = 64
anonymous
  • anonymous
thank you..maybe in the future ;p
ganeshie8
  • ganeshie8
ha :)

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