anonymous
  • anonymous
How do i find the asymptotes of y=5/(x+2)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
you mean |dw:1378150481156:dw| 5/(x+2) not 5/x+2
anonymous
  • anonymous
Yes, my bad.
anonymous
  • anonymous
anyhoo to find V asymptote you have to find x+2=0 cuzz that would make the denominator so little it will cause the graph to "shoot up" vertically and therefore it is a V asymptote.

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anonymous
  • anonymous
Can't it have an H asymptote also?
anonymous
  • anonymous
Now to find the H asymptote you plug in a very large number at x. typically chose 100, 1000, 100000 and you will see the graph get smaller and smaller. In fact it will reach zero and 0 is the H asymptote.
anonymous
  • anonymous
Is there a way i can find the H without plugging anything in?
anonymous
  • anonymous
y=0 is h asymptote x= -2 v asymptote
anonymous
  • anonymous
Why does y=0?
campbell_st
  • campbell_st
polynomial division is a simple way to find horizontal or oblique asymptotes |dw:1378150869977:dw| ignore the remainder and the quotient is the horizontal asymptote
anonymous
  • anonymous
well 5/(x+2) take that to be 5/a as you plug in a larger and largr number at x you get 5/a and a is larger and larger dividing 5 by a large number gets you 0
anonymous
  • anonymous
@campbell_st that is too complicated lol
campbell_st
  • campbell_st
lol... easier that limits...
campbell_st
  • campbell_st
and it works everytime
anonymous
  • anonymous
here is a rule (ax)/(bx) H asymptote will be be a/b EXAMPLE: 2x/(1x) = 2/1 ---- (ax)/(bx^2) Asymptote will be 0 THe above case states if the bottom polynomial is of a higher degree then asymptote will alwasy be 0 1000000x/.4x^2 = 0
campbell_st
  • campbell_st
so what happens when the degree of the numerator is greater than the degree of the denominator..?
anonymous
  • anonymous
Then there is no Horizontal Asymptote.
campbell_st
  • campbell_st
ummm interesting ... as the method for finding the oblique is the graph shown is the same as that used for finding the horizontal... division here is an example |dw:1378193922233:dw| the graph is attached ignore the remainder and the quotient is the horizontal or oblique asymptote

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