anonymous
  • anonymous
Help? x + 6 times (x - 8) = times (5x - 7) = ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
So far I've gotten: (x + 6) times (x - 8) = (x + 6)(x - 8) = x^2 - 8x + 6x - 48 = x^2 - 14x - 48 times (5x - 7) = (5x - 7)(x^2 - 14x - 38) = ?
e.mccormick
  • e.mccormick
-14x? \((x + 6)(x - 8)\ne x^2 - 14x - 48\)
anonymous
  • anonymous
Oops, okay. x^2 - 2 - 48?

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e.mccormick
  • e.mccormick
|dw:1378156096470:dw| Yah.
e.mccormick
  • e.mccormick
Now do the same thing with the \( (5x - 7)(x^2 - 2x - 38)\). Multiply 5x by every term in \((x^2 - 14x - 38)\) and write them down. Then multiply -7 by every term in \((x^2 - 14x - 38)\) and write them down. Then combined like terms.
e.mccormick
  • e.mccormick
And it is 48... made a type oand was using copy/paste.
anonymous
  • anonymous
Okay, let me jot this down.
anonymous
  • anonymous
Okay, so I got 5x^3 - 10x + 240x - 7x^2 + 14x + 41. Now I need to combine them, but does this look right?
e.mccormick
  • e.mccormick
I think you typoed something there....
anonymous
  • anonymous
Is it the 5x(48)?
e.mccormick
  • e.mccormick
-48
e.mccormick
  • e.mccormick
So lost a sign... that would do it.
anonymous
  • anonymous
Oh! Okay. 5x^3 - 10x - 240x - 7x^2 + 14x + 41.
e.mccormick
  • e.mccormick
- 10x? =P
anonymous
  • anonymous
+?
e.mccormick
  • e.mccormick
x?
e.mccormick
  • e.mccormick
\(5x\cdot -2x = -10x\)?
e.mccormick
  • e.mccormick
What happened to the \(x\cdot x\)?
anonymous
  • anonymous
5x(x^2) = 5x^3?
e.mccormick
  • e.mccormick
That is correct. But you dropped a square....
anonymous
  • anonymous
10x^2?
e.mccormick
  • e.mccormick
Yah. It happened when you distributed the 5x. Got to be careful of those!
anonymous
  • anonymous
Okay! 5x^3 - 10x^2 - 240x - 7x^2 + 14x + 41. Combine like terms.
anonymous
  • anonymous
Alright, so 5x^3 - 17x^2 - 226x + 41?
e.mccormick
  • e.mccormick
That last + 41.... that has an issue too. \(-7\cdot-48\ne -47\) You added 7 to -48. Oops.
anonymous
  • anonymous
Okay, 4x^3 - 17x^2 - 226x + 336.
e.mccormick
  • e.mccormick
Sometimes how you write things can make a huge difference, but you need to be very careful when doing side work! Any one number wrong will make the whole answer wrong. \(5x(x^2 - 2x - 48)=5x^3-10x^2-240x\) \(-7(x^2 - 2x - 48)=-7x^2+14x+336\) \((5x^3-10x^2-240x)+(-7x^2+14x+336)\) \(\begin{array}{rrrr} 5x^3&-10x^2&-240x& \, \\ \,&-7x^2&+14x&+336\\ \hline 5x^3&-17x^2&-226x&+336\\ \end{array}\) \(\therefore \; 5x^3-17x^2-226x+336\) \(\ddot\smile\)
anonymous
  • anonymous
Thank you so much!
e.mccormick
  • e.mccormick
np. I hope that helps you see a method to makeing these larger problems into smaller, easier ones. =)
anonymous
  • anonymous
Yeah, I'll make sure to follow how you write out problems. The way I write my problems gets confusing after a while.
e.mccormick
  • e.mccormick
Hehe. Well, no matter how you do it, develop an organized way and stick with it! it needs to make sense to you AND get the right answer.
anonymous
  • anonymous
Again, thank you so much. I'm gonna try to work on my next problem.
e.mccormick
  • e.mccormick
kk. Have fun!

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