anonymous
  • anonymous
evaulate the difference quotient f(x)=(x+3)/(x+1), f(x)-f(1)/x-1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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AkashdeepDeb
  • AkashdeepDeb
WELCOME TO OPENSTUDY!! :D
AkashdeepDeb
  • AkashdeepDeb
How much is f(1)? If f(x) = (x+3)/(x+1) Then f(1) = (1+3)/(1+1) = 4/2 = 2 So f(x) - f(1)/(x-1) = \(\frac{x+3}{x+1}\) - \(\frac{2}{x-1}\) Understood? :) Now calculate that! :D
anonymous
  • anonymous
isnt the x-1 should be under the whole thing

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AkashdeepDeb
  • AkashdeepDeb
The question is framed in such a way that it seems like it is under f(1) only. :D
AkashdeepDeb
  • AkashdeepDeb
Then calculate \[\frac { \frac{ x+3 }{ x+1 } - 2 }{x-1}\]
anonymous
  • anonymous
that is the part i am having problem with
anonymous
  • anonymous
forgot how to rationalize it
AkashdeepDeb
  • AkashdeepDeb
It is already rational no need to rationalize.. \[\frac{ (x+3) - 2(x+1) }{ (x+1)(x-1) }\] Getting this?
anonymous
  • anonymous
yes thank you! :D
AkashdeepDeb
  • AkashdeepDeb
:)

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