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Youd have to use an identity on the sin2x. Because you cant have different angles when youre solving these. SO you usr a double angle formul on sin2x to get everything int erms of just a single x angle. Do you know the double angle identity for sin2x?
Well, a lot of these you may be forced to remember unfortunately, so might as well write them down when they come up. So, sin2x = 2sinxcosx. Meaning youre actually trying to solve 2sinxcosx = sinx
So using that formula the equation will become 2sinxcosx=sinx then divide both sides by sinx which will leave you with sinxcosx as your answer
Well first off if you divide both sides by sinx you have 2cosx = 1. But even then you still have more work to do. You cant just solve for cosx or sinx, you have to solve for the actual x.
So what we need to do is get the cosx by itself, just as if we were solving for x. So that means I also want to divide both sides by 2 to give us cosx = 1/2 Now, do you have a unit circle chart handy?
Alright, cool. So there are two angles on the unit circle where cosx = 1/2. Just gotta find them.
Okay is it (cos, sin) on the unit circle
Yes, cos is x, sin is y
Okay so the angle would be 60
thats one of the 2.
Okay and the other is 300
Yep, those are your two answers then :3
So do you just write is as x=300 and 60 degrees
Thank you so much!
Yeah. np ^_^