anonymous
  • anonymous
Write the sum using summation notation, assuming the suggested pattern continues. -4 + 5 + 14 + 23 + ... + 131
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
First element is -4 Second elemnt is -4 + 9 Third element is -4 + 9 + 9 Nth element is -4 + 9*(n-1) Lets look at 131: 131 = -4 + 9*(n-1) --> n-1 = 15 --> n=16 So 131 is the 16th element \[\sum_{1}^{16} -4+9(n-1) = \sum_{1}^{16} -4+9n-9 = \sum_{1}^{16} 9n-13\]
anonymous
  • anonymous
Okay, that is the same answer I obtained, however it is not one of my choices.
anonymous
  • anonymous
Send your choices, let me have look at them

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anonymous
  • anonymous
Okay
anonymous
  • anonymous
|dw:1378160102473:dw|
anonymous
  • anonymous
Wow, I accidentally closed this.
anonymous
  • anonymous
\[\sum_{n=1}^{16} 9n-13 \rightarrow \sum_{k=0}^{15} 9k-4 \rightarrow \sum_{n=0}^{15} 9n-4\] There is a secret n in the top of the summation symbol. So 16 becomes 15
anonymous
  • anonymous
Okay, Thank You so much !

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