anonymous
  • anonymous
The probability that a vehicle entering the Luray Caverns has Canadian license plates is 0.12; the probability that it is a camper is 0.28; and the probability that it is a camper with Canadian license plates is 0.09. What is the probability that (a) a camper entering the Luray Caverns has Canadian license plates? (b) a vehicle with Canadian license plates entering the Luray Caverns is a camper? (c) a vehicle entering the Luray Caverns does not have Canadian plates or is not a camper?
Statistics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
it says The probability that a vehicle entering the Luray Caverns has Canadian license plates is 0.12 then asks What is the probability that (a) a camper entering the Luray Caverns has Canadian license plates?
anonymous
  • anonymous
not much to this is there?
anonymous
  • anonymous
so 0.12 is correct for the answer ?

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anonymous
  • anonymous
wel thanks for your help!
anonymous
  • anonymous
yes that is what it says right? not sure why you are told the answer and then asked the question seems weird to me
anonymous
  • anonymous
the others might require some work though
anonymous
  • anonymous
do you know how to do them?
anonymous
  • anonymous
but part says the probability that its a camper and canadian license... so would the answer for part a be 0.09??
anonymous
  • anonymous
part A*
anonymous
  • anonymous
part and and B sounds the same to me but inverted... so confused
anonymous
  • anonymous
k lets go slow and the first thing we should do is make a venn diagram, that will make all easier then we can read the questions carefully and see what exactly they are asking
anonymous
  • anonymous
|dw:1378168938734:dw|
anonymous
  • anonymous
okay so how did you get the 0.03 and 0.09 and 0.17
anonymous
  • anonymous
shouldnt it be .19 instead of .17
anonymous
  • anonymous
maybe i made a mistake let me check
anonymous
  • anonymous
ok the probability of the intersection is \(.09\) that is, the probability of both so i filled in the intersection first
anonymous
  • anonymous
yes so .28-.09 is .19 i think
anonymous
  • anonymous
then for the rest of A, since the total is \(0.12\) and we have already used up \(.09\) the remaining part is \(0.12-0.09=0.03\)
anonymous
  • anonymous
yeah you are right is screwed up
anonymous
  • anonymous
|dw:1378169421719:dw|
anonymous
  • anonymous
now lets answer this one What is the probability that a vehicle with Canadian license plates entering the Luray Caverns is a camper
anonymous
  • anonymous
if it is clear how to do it let me know and tell me what you get if not, i can show you how to do it quickly
anonymous
  • anonymous
would it be .19+.09 just excluding the .03??
anonymous
  • anonymous
no
anonymous
  • anonymous
wait would it be .19+.09+.03
anonymous
  • anonymous
not that either
anonymous
  • anonymous
i dont quite get the concept
anonymous
  • anonymous
lets make sure to understand the question
anonymous
  • anonymous
i understand the venn diagram but applying it i dont get
anonymous
  • anonymous
then it will be very easy
anonymous
  • anonymous
What is the probability that a vehicle with Canadian license plates entering the Luray Caverns is a camper means this you already KNOW the vehicle has a canadian plate
anonymous
  • anonymous
the question is, if you know it has a canadian plate, what is the probability that it is also a camper
anonymous
  • anonymous
lets imagine for a second that 100 vehicles come in then 12 would be canadian
anonymous
  • anonymous
of those 12, 9 would be campers so the probability that it is a camper if you already know it is canadian is the ratio \[\frac{9}{12}\]
anonymous
  • anonymous
which of course reduces to \(\frac{3}{4}\) in plain english, three fourths of the canadian vehicles are campers
anonymous
  • anonymous
clear or no?
anonymous
  • anonymous
i believe so.... so from the venn diagram i would look at as 0.09/.12 because we already know its a camper !
anonymous
  • anonymous
yes
anonymous
  • anonymous
that would give 3/4 as well
anonymous
  • anonymous
yes
anonymous
  • anonymous
i just got rid of the decimals to make it easier
anonymous
  • anonymous
since we are taking ratios anyway, they are kind of unnecessary
anonymous
  • anonymous
|dw:1378170206689:dw|
anonymous
  • anonymous
could have just as well used this hope it is clear where the 69 came from the total is 100
anonymous
  • anonymous
so part b would be 9/28 because we know that it is already candadian
anonymous
  • anonymous
no i dont get whre the 69 cam from
anonymous
  • anonymous
i got rid of the decimals and used percents total is 100%
anonymous
  • anonymous
and we already used up \(3+9+19\)
anonymous
  • anonymous
we did part B it was \(\frac{3}{4}\)
anonymous
  • anonymous
oh okay would part A be 9/28 then?
anonymous
  • anonymous
i get it so the rest that is not canadian or camper is 69/100
anonymous
  • anonymous
let me reread part A it is way up there now
anonymous
  • anonymous
yes, you are right for A, it is \(\frac{9}{28}\)
anonymous
  • anonymous
and you are also right for C
anonymous
  • anonymous
awesome thank you for your help!!
anonymous
  • anonymous
i have another problem that im working on as well could u help me with that one as well? i think i understand it . but i want to double check with you
anonymous
  • anonymous
Night engineers are going on an energy assessment in 3 cars that hold 2, 3, and 4 passengers, respectively. In how many ways is it possible to transport the 9 engineers to the manufacturing facility, using all cars?
anonymous
  • anonymous
i thought it to be permutation... so 9P3 ?? becasue there are 9 passengers and 3 cars....
goformit100
  • goformit100
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