anonymous
  • anonymous
How to find the equation of a line using only two coordinates?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
1. Determine the equation of the line, in standard form, that will get your spacecraft from the Launch Area to Point A. Launch Area:_(1, 2)_ Point A:_(6,7)_ Using these points, what would I need to do in order to answer the question? I'm not looking for answer more-so than I am trying to figure out how to do this. Thanks :)
anonymous
  • anonymous
If anyone could provide basic steps as to what to do, even that would help a ton. :)
anonymous
  • anonymous
First find slope. \[\frac{ y _{1}-y _{2} }{ x _{1} -x _{2} }\] After you find slope we will use the equation \[y-y _{1}=m(x-x _{1})\]

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anonymous
  • anonymous
Make sense?
anonymous
  • anonymous
Looks familiar enough, glad to know I was somewhat on the right path haha. I'll work it out and see what happens :)
anonymous
  • anonymous
Okay, if you feel uncertain feel free to post your work.
anonymous
  • anonymous
7-2 divided by 6-1 = 5/5 slope Plugging it in and converting it to standard form: y -2=5/5(x-1) y-2=5/5x-5/5 +2 +2 y= 5/5x-3/5 -5/5x -5/5x -5/5x + y = -3/5 x5 x5 x5 -5x + 5y = -3 My only question was on step 3 (when I added 2 to both sides), did I properly add it to the right side (I went from 5/5x - 5/5 *~to~* 5/5x -3/5)? @RoseDryer
anonymous
  • anonymous
Well since your slope is 5/5 that equals 1 So y - 2=1(x-1) y - 2 = x - 1 +2 +2 y= x + 1 -x -x -x + y = 1
anonymous
  • anonymous
Woah, looks like I'm way off. Let me try reworking it :)
anonymous
  • anonymous
y-y1=m(x-x1) y-2=1(x-1) y-2=1x+1 -1x -1x -1x + y = 1 How's that look?
anonymous
  • anonymous
@RoseDryer Not sure if I should mention you or not lol.
anonymous
  • anonymous
That's correct but you don't need the 1 in front of the x but you do keep the negative.

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