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ssgayle Group Title

Night engineers are going on an energy assessment in 3 cars that hold 2, 3, and 4 passengers, respectively. In how many ways is it possible to transport the 9 engineers to the manufacturing facility, using all cars?

  • one year ago
  • one year ago

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  1. ssgayle Group Title
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    what?

    • one year ago
  2. rushal Group Title
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    9C3 = . 9! ------- = 6! 3! 9 x 8 x 7 ------------- = 84 <==ANSWER 3 x 2 x 1 I hope that helps!! :-)

    • one year ago
  3. ssgayle Group Title
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    okay thats what i thought can you help me with one other problems?

    • one year ago
  4. rushal Group Title
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    sure if i can figure it out

    • one year ago
  5. ssgayle Group Title
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    A construction company employs two sales engineers, John and Meghan. John does the work of estimating cost for 70% of the jobs bid by the company. Meghan does the work for 30% of the jobs bid by the company. It is known that the error rate for John is such that 0.02 is the probability of an error when he does the work, whereas the probability of an error in the work of Meghan is 0.04. Suppose the bid arrives and a serious error occurs in estimating cost. Which engineer would you guess did the work? Explain and show work.

    • one year ago
  6. ssgayle Group Title
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    if u can that would be great!

    • one year ago
  7. satellite73 Group Title
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    why is it \(\binom{9}{3}\) ?

    • one year ago
  8. rushal Group Title
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    @satellite73 what bro ?

    • one year ago
  9. satellite73 Group Title
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    pretty sure that is not right

    • one year ago
  10. rushal Group Title
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    i guess but i m just trying to help -_-

    • one year ago
  11. satellite73 Group Title
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    you have \(9\) people to order in groups of 2, 3, and 4 i am fairly sure that the number of ways to do this is \[\frac{9!}{2!3!4!}\]

    • one year ago
  12. satellite73 Group Title
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    hey no problem, i just don't think "9 choose 3" is the right way to solve it

    • one year ago
  13. satellite73 Group Title
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    you have \(9!\) ways to order the people then divide by the number of ways to permute the people in each car

    • one year ago
  14. satellite73 Group Title
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    also notice that the "9 choose 3" approach ignores completely the number of people in each car

    • one year ago
  15. ssgayle Group Title
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    ooooo i see cause it has to be either 2 groups or 3 or 4... if it was just random groups then it could be 9 chose 3?

    • one year ago
  16. rushal Group Title
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    i got it too satellite73 is correct my bad -_-

    • one year ago
  17. satellite73 Group Title
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    9 choose 3 has really nothing to do with this problem it is the way to choose 3 things from a set of 9

    • one year ago
  18. satellite73 Group Title
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    it all comes from the counting principle |dw:1378173059624:dw|

    • one year ago
  19. ssgayle Group Title
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    would you be able to help me with another difficult problem satellite or rushal? A construction company employs two sales engineers, John and Meghan. John does the work of estimating cost for 70% of the jobs bid by the company. Meghan does the work for 30% of the jobs bid by the company. It is known that the error rate for John is such that 0.02 is the probability of an error when he does the work, whereas the probability of an error in the work of Meghan is 0.04. Suppose the bid arrives and a serious error occurs in estimating cost. Which engineer would you guess did the work? Explain and show work.

    • one year ago
  20. satellite73 Group Title
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    this is probably easiest if you do it with numbers lets imagine there are 1000 jobs total

    • one year ago
  21. satellite73 Group Title
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    700 are done by john, 300 by meghan

    • one year ago
  22. satellite73 Group Title
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    \(.02\times 700=14\) mistakes are made by john and \(.04\times 300=12\) by meghan

    • one year ago
  23. satellite73 Group Title
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    so it is pretty damned close, but john makes more mistakes

    • one year ago
  24. ssgayle Group Title
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    yea i wasnt quite sure what to do with the numbers but that makes sense since its a rate in in units work/ mistake

    • one year ago
  25. ssgayle Group Title
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    can we do one more proeblem... sorry i keep asking but these few have been bothering me

    • one year ago
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