A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 one year ago
How does newton's method work ? This is all supposed to be a review, but I'm having trouble remembering how it works...
f(x)=x^3 + x + 3 (Initial Guess = 1)
 one year ago
How does newton's method work ? This is all supposed to be a review, but I'm having trouble remembering how it works... f(x)=x^3 + x + 3 (Initial Guess = 1)

This Question is Closed

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1\[x_{n+1}=x_{n}\frac{f(x_n)}{f'(x_n)}\]

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1first guess is 1 \(f(1)=5\) so \(1\) is kind of a lousy guess, since you want it to be 0

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1\[f'(x)=3x^2+1\] so \[f'(1)=4\]

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1second guess is therefore \(x_2=1\frac{5}{4}=\frac{1}{4}\)

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1lather, rinse repeat it gets real messy real fast

jossy04
 one year ago
Best ResponseYou've already chosen the best response.0I'm kind of remembering how to do this

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1you can also do some algebra if you like before you start \[x\frac{f(x)}{f'(x)}=x\frac{x^3+x+3}{3x^2+1}\] \[=\frac{2x^33}{3x^2+1}\] and plug in there, but it amounts to the same thing

jossy04
 one year ago
Best ResponseYou've already chosen the best response.0Thank you very much for your help :)
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.