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my-geek-pride

  • 2 years ago

Use trig identites to transform the left side of equation into the right. (1+cos theta)(1-cos theta)= sin^2theta

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  1. AravindG
    • 2 years ago
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    1+cos theta =2cos^2 theta/2

  2. anonymous
    • 2 years ago
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    multiply on the left, and get \[1-\cos^2(\theta)\] then it should be easy enough

  3. AravindG
    • 2 years ago
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    1-cos theta=2sin^2 theta/2

  4. anonymous
    • 2 years ago
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    is it clear that \[1-\cos^2(\theta)=\sin^2(\theta)\]?

  5. my-geek-pride
    • 2 years ago
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    ooohh. yea. I see.

  6. anonymous
    • 2 years ago
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    kk good

  7. my-geek-pride
    • 2 years ago
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    thank you(:

  8. anonymous
    • 2 years ago
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    yw

  9. goformit100
    • 2 years ago
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    "Welcome to OpenStudy. I can guide regarding this useful site; ask your doubts from me, for it you can message me. Please use the chat for off topic questions. And remember to give the helper a medal, by clicking on "Best Answer". We follow a code of conduct, ( http://openstudy.com/code-of-conduct ). Please take a moment to read it."

  10. adila98
    • 2 years ago
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    use identity ---> a^2 - b^2 for lhs then prove using cos2 + sin2 = 1

  11. mjithin
    • 2 years ago
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    (1+cosθ)(1−cosθ)=(1−cosθ+cosθ−cos2θ) = sin2theta

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