last vector question - application

- anonymous

last vector question - application

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

- chestercat

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- anonymous

##### 1 Attachment

- anonymous

Find the unit vectors of each rope. Scale them by the pounds of force they have. Add the vectors up, then find the magnitude of that vector.

- anonymous

dude can plz go step by step ... i m confused

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

Can you find the unit vectors for the ropes?

- anonymous

Everything you have been doing for has lead up to this point.

- amistre64

im thinking more along the lines of calculating the trig stuff involved

- amistre64

|dw:1378221930615:dw|

- amistre64

im assuming it wants a resultant vectors maybe?

- ganeshie8

interesting.. . yes it wants resultnat of T1 and T2

- anonymous

yes ,it is asking for the force exerted on point A

- amistre64

(8,10,6) @ 420
(-10,10,6) @ 650

- amistre64

find the magnitude of each vector, and scale it to obtain the stated Tension ... then add the results and find the magnitude/direction

- amistre64

im assuming the point A to be associated with the x axis, and positive to be towards us .... just the way i saw it initially is all

- anonymous

alright the magnitude would be 10 sqrt(2) and 2sqrt(59)

- anonymous

wait am i lost somwhere

- amistre64

good, so multiply the vector parts by say:
420/(10sqrt2)
and
650/(2sqrt59)

- amistre64

this should represent the appropriate forces instead of just distances

- anonymous

42/sqrt(2) and 325/sqrt(59)

- amistre64

if simplifying as you go is what you want to do ... then thats fine
scale out the vectors now

- anonymous

how?

- amistre64

(8a/b,10a/b,6a/b)
(-10n/m,10n/m,6n/m)

- amistre64

\[k(x,y)=(kx,ky)\]

- amistre64

then its just adding the parts ...
x = 8a/b-10n/m
y = 10a/b+10n/m
z = 6a/b+6n/m

- anonymous

ok i m confused where r u getting this a,b and n,m

- amistre64

im not going to sit there and write out all the specifics that we found all over again .... so i just represented them in some generic form

- anonymous

is there a easy way to figure out the solution

- anonymous

lol

- amistre64

a/b represents the 420/10sqrt2
n/m represents the 620/2sqrt59

- amistre64

using a calculator is the easiest way ....

- anonymous

haha so whats the answer

- amistre64

x = 8a/b-10n/m
y = 10a/b+10n/m
z = 6a/b+6n/m

- amistre64

that gives us the direction; the magnitude of that is the "applied Force"

- anonymous

did we use unit vector

- amistre64

in a way yes. we divided by the original magnitudes (unit them), then scaled them by their respective forces.

- anonymous

isn't the force scalar

- amistre64

magnitiude and force are scalar quantities

- anonymous

alright thx

- amistre64

youre welcome, and good luck

- anonymous

alright so here we r finding vector ab and ac and them their magnitude

- anonymous

then whats the step where we r dividing 420 / ab and 650/ac @ganeshie8

- ganeshie8

yes ! first find the magnitude, then divide it by the tension

- anonymous

ya what is that step called, like is it \[F_{1}\]

- anonymous

F1 = tension/ magnitude of ab

- ganeshie8

T1 is already given as 420
T2 is already given as 650
F1 is same as T1
F2 is same as T2

- ganeshie8

but they're just magnitudes,
to add the forces you need directions also
so we find the coordinates for points A, B and C

- ganeshie8

lets fix A at (0,0,0)

- anonymous

ok so i have tension of ab coordinates and magnitude of ab....

- ganeshie8

can you find B and C relatice to A ?

- anonymous

(8,10,6) and c = (-10,10,6)

- ganeshie8

now multiply your scaled forces(scalar) wid these coordinates, that gives you direction also to the forces
then you can add them

- anonymous

so plzzzz hurry, just 7 minutes....add what and what ab and ac???

- ganeshie8

ab = magnitude of AB = ||<8,10,6||
ac = magnitude of AC = ||<-10,10,6||

- anonymous

ya i got ||ab|| = 10 sqrt(2) and bc = 2 sqrt(59)

- ganeshie8

scale the given forces/tensions nw
420 / ab and 650/ac

- anonymous

why

- ganeshie8

good q, cuz you're given the magnitude of forces. to account for the direction of resultant force in space, you need to scale the given force along the direction of rope
(il give better explanation ltr)

- anonymous

thx got that part 2 min whats last part

- ganeshie8

add both the forces

- ganeshie8

420/ab <8,10,6> + 650/ac <-10,10,6>

- ganeshie8

that gives u a force vector

- ganeshie8

take its magnitude to get the force in pounds

- anonymous

72 pounds and at last i will get x y and z right?

- anonymous

yes or no

- ganeshie8

dint get u, force is just a number

- ganeshie8

just give them the number, you dont need to given them components

- anonymous

alright thx bye

- ganeshie8

np :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.