anonymous
  • anonymous
solve the equation 3√27 = 3^3x
Calculus1
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
|dw:1378188059898:dw|
anonymous
  • anonymous
|dw:1378188237662:dw|
anonymous
  • anonymous
|dw:1378188317531:dw|

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anonymous
  • anonymous
what do after that?
Luigi0210
  • Luigi0210
There's only one method that I know will work, graphing both and seeing where they intersect
anonymous
  • anonymous
no you could make the bases the same and solve the exponents
anonymous
  • anonymous
how would i make the bases the same? put them all over 1?
anonymous
  • anonymous
Well we have \(3\sqrt{27}=3^{3x}\)so we want to get base \(3\)\[3\sqrt{27}~~~\implies~~~9\sqrt{3}~~~\implies~~~\large 3^{5\over2}\]so now we have :\[3^{5\over2}=3^{3x}\]\[{5\over2}=3x\]\[x={5\over6}\]
JMark
  • JMark
Given 3√27 = 3^3x 3√(3*3*3)=27x 9√3=27x divide by 27 x=1/√3

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