anonymous
  • anonymous
The velocity of a ball thrown vertically upwards\ from ground level is v(t)= -32t^2 + 64t, where t is the time in seconds and v is the velocity in feet per second. Find the time when the ball reaches its maximum height (Find the vertex of the parabola using x= -b/ 2a
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Psymon
  • Psymon
Well, it gives you the hint -b/2a. Well, a norma quadratic function is ax^2 + bx + c The number in front of the x^2 is 'a" and the number in front of x is b. Except for you you have t, but same thing. So in your case, b is 64 and a is -32. So plugging those into the formula will give you the time it takes to reach the maximum height.
Psymon
  • Psymon
So if done correctly, you should have -64/-64 = 1. Which means it is at its maximum height after 1 second. In order to actually find that height, you replace t with 1 in the original equation, meaning you solve -32(1)^2 + 64(1) = ?
anonymous
  • anonymous
-960

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anonymous
  • anonymous
sorry wrong
Psymon
  • Psymon
Take your time :3
anonymous
  • anonymous
is that a plus sign ?
Psymon
  • Psymon
-32(1)^2 + 64(1) So yeah, plus sign in the middle.
anonymous
  • anonymous
32
Psymon
  • Psymon
Yep : )
anonymous
  • anonymous
perfect, thank you (:
Psymon
  • Psymon
no problem :3

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