anonymous
  • anonymous
what must be added to x3 - 3x2 - 12x + 19 so that the result is exactly divisible by x2 + x -6 ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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AkashdeepDeb
  • AkashdeepDeb
WELCOME TO OPENSTUDY!! :D
anonymous
  • anonymous
divide dem both
anonymous
  • anonymous
Is it your question ?: 3x - 6 - 12x +19 ? If we have that can write it : -9x+9 And can write the 2th sentence this : 3x-6 Now we should reduce the 2th from 1th sentence . It s : 3x-6-(-9x+9)=3x-6+9x-9=12x-15 Understand?!:)

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anonymous
  • anonymous
@E.ali dude u had interpreted wrongly actually question is x^3-3x^2-12x+19 -------------equation 1 x^2+x-6 --------equation 2 @queen151999 Ans will be equation 1 / equation 2 which will be equal to -2x-5
DebbieG
  • DebbieG
No, not quite. The question is: if f(x)= \(x^3-3x^2-12x+19 \) & g(x)=\(x^2+x-6 \) then what must be ADDED to f(x) so that the division f(x)/g(x) has NO remainder?
DebbieG
  • DebbieG
since \(x^2+x-6 =(x+3)(x-2)\), those will both need to be factors of the revised f(x) when you're finished with it.
DebbieG
  • DebbieG
I think the idea is just to find a factor (x-a) so that \((x+3)(x-2)(x-a)=x^3-3x^2-12x+19+h(x)\) The easiest way is just to pick an a, find that product, and then see what you need to add to \(x^3-3x^2-12x+19\) to GET that. Whatever you have to add, that will be your h(x).
goformit100
  • goformit100
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