what must be added to x3 - 3x2 - 12x + 19 so that the result is exactly divisible by x2 + x -6 ?
Stacey Warren - Expert brainly.com
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divide dem both
Is it your question ?:
3x - 6 - 12x +19 ?
If we have that can write it :
And can write the 2th sentence this :
Now we should reduce the 2th from 1th sentence .
It s :
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dude u had interpreted wrongly
actually question is x^3-3x^2-12x+19 -------------equation 1
x^2+x-6 --------equation 2
Ans will be equation 1 / equation 2 which will be equal to -2x-5
No, not quite. The question is:
if f(x)= \(x^3-3x^2-12x+19 \)
& g(x)=\(x^2+x-6 \)
then what must be ADDED to f(x) so that the division f(x)/g(x) has NO remainder?
since \(x^2+x-6 =(x+3)(x-2)\), those will both need to be factors of the revised f(x) when you're finished with it.
I think the idea is just to find a factor (x-a) so that
The easiest way is just to pick an a, find that product, and then see what you need to add to \(x^3-3x^2-12x+19\) to GET that. Whatever you have to add, that will be your h(x).
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