The general value of X in the equation 2sin2x= sinx is:
a.nPie+Pie/2 b.npie/4 c. 2npi+pie/2
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use sin2x =2sin x cos x
something gets cancelled out, what ?
and then? 4sinx cosx = sinx
you will consider sin x =0 too
4 sin x cos x = sin x
----> sin x (4cos x-1) = 0
sin x =0 or 4 cosx-1 =0
got this ?
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theres 2sin2x ..??? not only sin2x
can you solve 4cos x-1 = 0 ?
well, but with that, you would not get any choice as your answer....because 1/4 is not the cos value of any standard angle...
you sure the Q is correct ?
yeah it was in a book
Yeah, that factor of 2 in front is definitely a sticky widget here!
@rajatgang , be careful, you can NOT divide through by sin(x) in this equation!! Must set is all = 0 and factor. Never divide by an unknown that might be =0.
im trying it....
i guess question is wrong ....
With those as the answer choices? Hmm. Well, books have been known to have errors in them. I dunno, this doesn't look right, and you can punch it into Wolfram and see that none of those are the complete solution set.
Even if you remove the 2 in front on the LHS, you don't get any of those as the complete solution set.
Here is a step by step solution: