anonymous
  • anonymous
find the center of masses of the plane area bounded by the parabolas y=2x-x^2 and y=3x^2-6X
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
what math class is this from?
anonymous
  • anonymous
the method I see uses calculus
anonymous
  • anonymous
@mbugwav you can't leave me to do this alone

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anonymous
  • anonymous
PETER 14 I AGREEit can be solved using calculus
anonymous
  • anonymous
dan815 yes it will what about x bar?
dan815
  • dan815
i will restart
dan815
  • dan815
|dw:1378206924244:dw|
anonymous
  • anonymous
https://www.desmos.com/calculator/qcshlnluve have a graph
dan815
  • dan815
or maybe 1/ b-a ?
anonymous
  • anonymous
this problem can be solved by using the knowledge the area
dan815
  • dan815
|dw:1378207580735:dw|
anonymous
  • anonymous
I am going to type the equation just now, then we can take it from there
anonymous
  • anonymous
\[\frac{ \int\limits_{A}^{}xdA }{ \int\limits_{A}^{} dA}\]
anonymous
  • anonymous
peter i appreciate dan815 what are the centers
dan815
  • dan815
|dw:1378207611672:dw|
dan815
  • dan815
does -2/3 for y bar make sense?
anonymous
  • anonymous
what about x bar
dan815
  • dan815
im thinking that is just 1
dan815
  • dan815
but what about ybar?? i am trying some sktechy logic
dan815
  • dan815
lets wait and see how pneew does it
anonymous
  • anonymous
alright
anonymous
  • anonymous
dan how did you get x=1?
dan815
  • dan815
just avg, they intersection at 0 and 2 so i said 1
anonymous
  • anonymous
dA stand for the derivative of an Area
anonymous
  • anonymous
\[dA=(2x-x^2)-(3x^2-6x)dx\]
anonymous
  • anonymous
sorry guys, I think I have a solution here, maybe if you may consider what i'm trying to post
anonymous
  • anonymous
area =16/3
anonymous
  • anonymous
\[ \frac{ \int\limits_{0}^{2}x(2x-x^2)-(3x^2-6x)dx}{ \int\limits_{0}^{2} ((2x-x^2)-(3x^2-6x)dx}\]
anonymous
  • anonymous
i am getting y bar as -0.4
anonymous
  • anonymous
simple put dA in the equation
anonymous
  • anonymous
then you integrate that, since this is a calculus question
dan815
  • dan815
alright mbugwav ill use that formula
dan815
  • dan815
that shud be 3/16
dan815
  • dan815
let me check your area just in case
anonymous
  • anonymous
yes, sir that shud be 3/16, that will give 1, which means x=1
dan815
  • dan815
ok
anonymous
  • anonymous
true bcause its the reciprocal but why not\[-4x^2\]
anonymous
  • anonymous
for y, |dw:1378209580611:dw|
anonymous
  • anonymous
now,\[y=(2x-x^2)+(3x^2-6x)\]
anonymous
  • anonymous
i agree
anonymous
  • anonymous
dA is the same, then you put what you have in the equation of y
dan815
  • dan815
|dw:1378210124670:dw|
dan815
  • dan815
spotted a mistake
dan815
  • dan815
anyway go on
anonymous
  • anonymous
|dw:1378210072047:dw|, than you integrate
dan815
  • dan815
|dw:1378210239272:dw|
dan815
  • dan815
use this formula
dan815
  • dan815
http://www.youtube.com/watch?v=H5RcfMIZ_yw
dan815
  • dan815
use that formula there
dan815
  • dan815
for y bar
anonymous
  • anonymous
okay
anonymous
  • anonymous
sorry guys i have to go to do my praticals, dan is correct, but i think |dw:1378210681566:dw|, if you can integrate this correctly you find the answer.
anonymous
  • anonymous
thakns guys i have to go
goformit100
  • goformit100
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