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raebaby420
Group Title
Please help. c:
If the linear equation is Y=4x+1, describe how to solve where your equation and the meteor’s path will cross. Explain any possible methods used in discovering a solution.
 one year ago
 one year ago
raebaby420 Group Title
Please help. c: If the linear equation is Y=4x+1, describe how to solve where your equation and the meteor’s path will cross. Explain any possible methods used in discovering a solution.
 one year ago
 one year ago

This Question is Closed

DebbieG Group TitleBest ResponseYou've already chosen the best response.1
Do you have an equation for the meteor's path? You're missing some information here.
 one year ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
No, it didn't give me it.. let me double check
 one year ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.1
I know that y=4x+1 is your equation from the last problem, but you're going to need to post all the problem info. This is the first I've heard of a meteor, lol.
 one year ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
It doesn't tell me what the meteors trajectory is
 one year ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.1
Post the whole problem. This is not a standalone problem. There is missing info.
 one year ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.1
Is there a diagram or something?
 one year ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
I think what its asking me is if I had that info what would I do to solve where they would cross since I have my linear equation
 one year ago

skullpatrol Group TitleBest ResponseYou've already chosen the best response.0
It could be simply asking where y=4x + 1 intercepts the xaxis.
 one year ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
Heres the question: If the linear equation of the meteor’s path is known, describe to the captain how to solve where your equation from question 1 and the meteor’s path will cross. Explain any possible methods used in discovering a solution.
 one year ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.1
Ah, ok. Just DESCRIBE how to FIND the solution.
 one year ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
It just wants to know how would I solve to find out where the would cross..
 one year ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.1
What do you think? You would have 2 equations... you want to find a point that is on the graph of BOTH equations. how do you do that?
 one year ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.1
Oh, and it helps that you are told that the meteor's path is modeled by a LINEAR equation. So both are lines.
 one year ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
Sorry..
 one year ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
I don't remember how to do that.
 one year ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
Id do it all in my calculator if i could..
 one year ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
butt im assuming that i would make the x and y chart and graph my lines.. am i correct?
 one year ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.1
Don't remember? isn't this topic being covered in your class? No, don't resort to your calculator all the time. It's a useful tool, but it doesn't teach you the CONCEPT.
 one year ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.1
Graphing is one possible method, although it's not very precise.
 one year ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
Mm im doing credit recovery.. so im trying to understand it. i failed algebra 2 because i wasn't paying attention in school and now im a senior and struggling.
 one year ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
Well ok, i want the most precise way. Would that be solving the liner equation? Im not sure...
 one year ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.1
If you have two equations, say: y=4x+1 y=3x+5 and you want to find a point that is on BOTH of the lines, then you are looking for an (x,y) pair that satisfies BOTH equations. This is called a "system of 2 linear equations in 2 unknowns".
 one year ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
Ok.. sounds sorta familiar how do i find the pair?
 one year ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.1
Now, I conveniently wrote both of these in the form y={some stuff}... but that's OK, because you can ALWAYS transform a linear equation into that form (so long as it isn't a VERTICAL line, that's the only time you can't). So since y={some stuff} and y={some other stuff}.... the easiest thing in this case is probably to set the "stuffs" equal to one another. That is, they are both =y, so they are both = each other, see that?
 one year ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.1
That's called "substitution", because I have one equation (actually both in this case, but one is enough) solved for ONE variable, and then I'm PLUGGING THAT IN ("substituting") in the other equation where I see that variable.
 one year ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
I know of substitution.. but i don't remember how to do it. ive done it before though, quite a few times.
 one year ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.1
So, in my madeup example, I would have: 4x+1=3x+5 And now I would solve THAT for x, just by moving the terms around (add 3x to both sides, subtract 1 from both, and then divide by the coefficient on the x term)
 one year ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.1
OK, that's fine... that's why I'm walking you through it. :) You should know how to do this, so it's good that you are going back to relearn it now.
 one year ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.1
Now, once I solve that equation, I'll have a VALUE, a number, for x. That's my x for my solution. Now I just need y. Well, I have two equations, and again  remember what this solution must be: an (x,y) pair that satisfies BOTH equations. So NOW I'm going to take that x I just found, and plug it into either equation, and solve for y. Check the solution (plug both x and y into both equations, and they should be true). After you confirm that it works, THAT is your solution to the system.
 one year ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.1
Graphically, it looks like this: dw:1378209299923:dw
 one year ago
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