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emcrazy14
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 1+x }{ \sqrt{1x} }\]

satellite73
 one year ago
Best ResponseYou've already chosen the best response.2expand in a power series i take it

satellite73
 one year ago
Best ResponseYou've already chosen the best response.2about zero i hope first term is \(f(0)=1\)

satellite73
 one year ago
Best ResponseYou've already chosen the best response.2first derivative is \[f'(x)=\frac{3x}{2\sqrt{1x}^3}\] so second term is \[f'(0)x=\frac{3}{2}x\]

satellite73
 one year ago
Best ResponseYou've already chosen the best response.2yikes, now we need the derivative of that beast

satellite73
 one year ago
Best ResponseYou've already chosen the best response.2do i have to do that too?

satellite73
 one year ago
Best ResponseYou've already chosen the best response.2looks like it is \[f''(x)=\frac{7x}{4\sqrt{1x}^5}\]

satellite73
 one year ago
Best ResponseYou've already chosen the best response.2making the next term \[\frac{f''(0)}{2}x^2=\frac{7}{8}x^2\]

emcrazy14
 one year ago
Best ResponseYou've already chosen the best response.0So I find the derivative of that too?

satellite73
 one year ago
Best ResponseYou've already chosen the best response.2\[f'^{(3)}(x)=\frac{333x}{8\sqrt{1x}^7}\]

satellite73
 one year ago
Best ResponseYou've already chosen the best response.2if so then \(\frac{f^{(3)}(0)}{3!}x^3=\frac{33}{16}x^3\)

satellite73
 one year ago
Best ResponseYou've already chosen the best response.2hmm let me check if this is right

satellite73
 one year ago
Best ResponseYou've already chosen the best response.2no messed up \(3!=6\) doh

satellite73
 one year ago
Best ResponseYou've already chosen the best response.2third term is \(\frac{11}{16}x^3\)

satellite73
 one year ago
Best ResponseYou've already chosen the best response.2k lets check the whole dam thing and see if it is right

satellite73
 one year ago
Best ResponseYou've already chosen the best response.2http://www.wolframalpha.com/input/?i=%281%2Bx%29%2Fsqrt%281x%29 yup !!

emcrazy14
 one year ago
Best ResponseYou've already chosen the best response.0Okay, thank you so much! :)
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