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anonymous
 2 years ago
Urgent help needed:
Expand the following up to the term in x^3:
anonymous
 2 years ago
Urgent help needed: Expand the following up to the term in x^3:

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anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 1+x }{ \sqrt{1x} }\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0expand in a power series i take it

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0about zero i hope first term is \(f(0)=1\)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0first derivative is \[f'(x)=\frac{3x}{2\sqrt{1x}^3}\] so second term is \[f'(0)x=\frac{3}{2}x\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0yikes, now we need the derivative of that beast

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0do i have to do that too?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0looks like it is \[f''(x)=\frac{7x}{4\sqrt{1x}^5}\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0making the next term \[\frac{f''(0)}{2}x^2=\frac{7}{8}x^2\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0So I find the derivative of that too?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0\[f'^{(3)}(x)=\frac{333x}{8\sqrt{1x}^7}\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0if so then \(\frac{f^{(3)}(0)}{3!}x^3=\frac{33}{16}x^3\)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0hmm let me check if this is right

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0no messed up \(3!=6\) doh

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0third term is \(\frac{11}{16}x^3\)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0k lets check the whole dam thing and see if it is right

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=%281%2Bx%29%2Fsqrt%281x%29 yup !!

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Okay, thank you so much! :)
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