Differential Equations Initial Value Problem
I worked it out, but I arrived at a different answer than is given in my text book.
\(ty\prime + (t+1)y=t\)
\(y(\ln(2))=1,~t>0\)

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I arrived at
y = t + 1 - ln(2)
My books answer....
\(y=\dfrac{(t-1+2e^{-t})}{t},~t\ne0\)

You have a new DE and you didn't invite me? T.T

@terenzreignz :P

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