Given the equation 2 Square root of x minus 5 = 2, solve for x and identify if it is an extraneous solution.
x = 6, solution is not extraneous
x = 6, solution is extraneous
x = 11, solution is not extraneous
x = 11, solution is extraneous

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@meganemma1995 What exacrly do you mean by 2square root? :D

2√x-5=2

@AkashdeepDeb

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