anonymous
  • anonymous
help with linear inequality systems?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
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anonymous
  • anonymous
is that university math cause i think my brain just died
anonymous
  • anonymous
lol it's precalc @paul1231

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jdoe0001
  • jdoe0001
so, exercise 2) only has 1 inequality, that means it's only one line the line to be graphed from the inequality \(\bf y \le x\) would be \(\bf y = x\)
jdoe0001
  • jdoe0001
well, 2) actually has 2 inequalities \(\bf x\ge 0\\ y\le x\) exercise 3) has 4 inequallities \(\bf 0 \le x \le 4 \implies 0 \le x \ and \ x \le 4\\ ---------\\ y \le x\\ x+y \ge 4\)
jdoe0001
  • jdoe0001
so lemme do the 1st one, 2) those 2 inequalities will have 2 graphs, x = 0 and y = x|dw:1378237209984:dw|
jdoe0001
  • jdoe0001
those alone are the 2 lines for 2) so test for what are would be the SHADED or TRUE part of the graph, we test points NOT in the line
jdoe0001
  • jdoe0001
so let's test say ( 1, 2) x = 1, y = 2 \(\bf x \ge 0 \implies 1 \ge 0 \textit{ is 1 bigger than 0? yes thus TRUE}\\ y \le x \implies 2 \le 1 \textit{ is 2 smaller than 1? no, thus FALSE}\) so that point didn't work, one yielded true the other false, same point values, thus on that area where (1, 2) is at, is not shaded or is false, or "is not part of the solution"

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