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2 persons work together in 25 days. How many days if 1 person works alone? Cannot be hard for you, right?
take it simple, you and me work in 2 days, only you work, it must take double the time you work with me, right?
@msingh I am sorry, I am not good at explanation. Let e.mccormick guide you
One worker is going faster than the other. The goal is to find the speed of each, working alone. The unitary method is about finding a basic unit, then multiplying it.
oops, e.mccormick is right. aaaaahh, @msingh ignore my comments, please.
If you think about it, each person is doing a percentage of the job. So, \(A\%\cdot 25 + B\%\cdot 25=100\%\) BUT, that does not happen. They give you another solution. That gives you two equations in two variables that equal the same thing. Once you make that second equation, solving this should not be too hard.
So, do you see what the other formula would be? Also, it is probably easier to use decimal numbers than percentage.
srry i m not getting it
Well, can you see where my formula there relates to the question? "A and B can do a job in 25 days. After 15 days of working together, B leaves. If A completed the remaining part of the job in 20 days, how long will each take to complete the job working separately."
can u solve it