anonymous
  • anonymous
solving for y again... tan(3y+2)=x^2+5
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
I have so far y=1/3((x^2+5)/tan-2)
anonymous
  • anonymous
For this question you would have to do a bit of trig. First to get rid of the tan on the left side you have to do the tangent inverse to both sides.
anonymous
  • anonymous
So it would actually be y=(1/3)tan^/1(x^2+5)-2 ?

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anonymous
  • anonymous
-1 *
anonymous
  • anonymous
You have the right answer but wrong notation. Parenthesis make a big difference. It should be Y=(tan^-1(x^2+5))/3-2
anonymous
  • anonymous
dont forget the -1 in the exponent. Its the inverse.
anonymous
  • anonymous
but the whole equation would be subtracted by 2 not just (x^2+5)?
anonymous
  • anonymous
Yeah so it should look exactly like this. \[Y=(\frac{ \tan^{-1}(x^2+5)}{ 3})-2\]
anonymous
  • anonymous
Perfect :) thank you again!
anonymous
  • anonymous
No problem! :D Anytime!

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