anonymous
  • anonymous
Can someone double check my work?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
2. \[(-3x^5)(2xy^4)(6xy)^0\] I got: \[-3x^5(2xy^4) \] \[= -6x^6y^4(1)\] \[= -6x^6y^4\] (final answer)
anonymous
  • anonymous
Also, 3. \[\left(\begin{matrix}xyz^3 \\ y^5w^-7\end{matrix}\right)\] Which I got: \[\frac{ xyz^3w^7 }{ y^5}\]
ivettef365
  • ivettef365
it looks good

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

ivettef365
  • ivettef365
you can subtract the y on top with bottom
anonymous
  • anonymous
Oops, there isn't supposed to be a parentheses for #3. And okay, so: \[\frac{ 1}{ xy^-5z^3w^7 } \]
ivettef365
  • ivettef365
this is a new problem ?
anonymous
  • anonymous
Oh no, that was supposed to be the answer to the problem.
ivettef365
  • ivettef365
why did you change it ?
ivettef365
  • ivettef365
you had it right the only thing you have to do is subtract the y and you get xz^3w^7 -------- y^4
anonymous
  • anonymous
Oh, okay. I had subtracted 1 from 5 and got -4 and then flipped the equation. Thank you for your help.

Looking for something else?

Not the answer you are looking for? Search for more explanations.